Question

The fuel used in many disposable lighters is liquid butane, C4H10. Butane has a molecular weight of 58.1 grams in one mole. How many carbon atoms are in 1.00 g of butane?

Answer 1

Answer : The number of carbon atoms present in butane are $4.14\times 10^{22}$

Explanation : Given,

Molar mass of $C_4H_{10}$ = 58.1 g/mole

Mass of $C_4H_{10}$ = 1.00 g

First we have to calculate the number of moles of butane.

$\text{Moles of }C_4H_{10}=\frac{\text{Mass of }C_4H_{10}}{\text{Molar mass of }C_4H_{10}}$

$\text{Moles of }C_4H_{10}=\frac{1.00g}{58.1g/mole}=0.0172mole$

Now we have to calculate the number of carbon atoms present in butane.

In butane, there are 4 atoms of carbon and 10 atoms of hydrogen.

As we know that, 1 mole of substance contains $6.022\times 10^{23}$ number of atoms.

As, 1 mole of butane contains $4\times 6.022\times 10^{23}$ number of carbon atoms.

So, 0.0172 mole of butane contains $0.0172\times 4\times 6.022\times 10^{23}=4.14\times 10^{22}$ number of carbon atoms.

Therefore, the number of carbon atoms present in butane are $4.14\times 10^{22}$

Answer 2

2iekfjdjabnfwnfuwj ag hbn few nbfnbfb