All categories

3 years ago

Is table salt and chalk a homogeneous or heterogeneous mixture?

2 answers:

8 0

Table salt is uniform in state when mixed with water as it dissolves so therefore table salt is homogeneous and chalk is heterogeneous because even grounded up it is still a cloudy substance and you would not be able to see through it :)

Dovator [93]3 years ago

3 0

The answer is heterogeneous

You might be interested in

What is the name of CrO2?

svlad2 [7]

The name is chromium oxide!

7 0

2 years ago

A negatively charged balloon comes close to a positively charged cloth. What will happen?

Elena L [17]

The balloon will attract the cloth I think. Opposites attract so

7 0

3 years ago

Read 2 more answers

Over the years, the thermite reaction has been used for years to welding railroad nails, in cendiary bombs, and to ignite solid

koban [17]

Answer:

A. 109.61 g of Fe₂O₃

B. 36.99 g of Al

C. Maximum mass of Al₂O₃ produced is 69.90 g

Explanation:

The balanced equation for the reaction is given below:

Fe₂O₃ (s) + 2Al (s) → 2Fe (l) + Al₂O₃ (s)

Next, we shall determine the masses of Fe₂O₃ and Al that reacted and the masses of Fe and Al₂O₃ produced from the balanced equation. This can be obtained as follow:

Molar mass of Fe₂O₃ = (2×56) + (3×16)

= 112 + 48 = 160 g/mol

Mass of Fe₂O₃ from the balanced equation = 1 × 160 = 160 g

Molar mass of Al = 27 g/mol

Mass of Al from the balanced equation = 2 × 27 = 54 g

Molar mass of Fe = 56 g/mol

Mass of Fe from the balanced equation = 2 × 56 = 112 g

Molar mass of Al₂O₃ = (2×27) + (3×16)

= 54 + 48 = 102 g/mol

Mass of Al₂O₃ from the balanced equation = 1 × 102 = 102 g

SUMMARY:

From the balanced equation above,

160 g of Fe₂O₃ reacted with 54 g of Al to produce 112 g of Fe and 102 g of Al₂O₃

A. Determination of the mass of iron(III) oxide, Fe₂O₃, needed to produce 76.73 g of iron, Fe.

From the balanced equation above,

160 g of Fe₂O₃ reacted to produce 112 g of Fe.

Therefore, Xg of Fe₂O₃ will react to produce 76.73 g of Fe i.e

Xg of Fe₂O₃ = (160 × 76.73)/112

Xg of Fe₂O₃ = 109.61 g

Thus, 109.61 g of Fe₂O₃ is needed to produce 76.73 g of Fe.

B. Determination of the mass of aluminum, Al, to produce 76.72 g of iron, Fe.

From the balanced equation above,

54 g of Al reacted to produce 112 g of Fe.

Therefore, Xg of Al will react to produce 76.72 g of Fe i.e

Xg of Al = (54 × 76.72)/112

Xg of Al = 36.99 g

Thus, 36.99 g of Al is needed to produce 76.72 g of Fe.

C. Determination of the maximum mass of aluminum oxide, Al₂O₃, produced along with 76.75 g Fe.

We'll begin by calculating the mass of Fe₂O₃ needed to produce 76.75 g of Fe. This is illustrated below:

From the balanced equation above,

160 g of Fe₂O₃ reacted to produce 112 g of Fe.

Therefore, Xg of Fe₂O₃ will react to produce 76.75 g of Fe i.e

Xg of Fe₂O₃ = (160 × 76.75)/112

Xg of Fe₂O₃ = 109.64 g

Thus, 109.64 g of Fe₂O₃ is needed to produce 76.75 g of Fe.

Finally, we shall determine the maximum mass of Al₂O₃ produced along with 76.75 g Fe. this can be obtained as follow:

From the balanced equation above,

160 g of Fe₂O₃ reacted 102 g of Al₂O₃.

Therefore, 109.64 g of Fe₂O₃ will react to produce = (109.64 × 102)/160 = 69.90 g of Al₂O₃.

Thus, the maximum mass of Al₂O₃ produced is 69.90 g

6 0

2 years ago

Hydrogen and Oxygen will have ______ properties after they bond to become water.

saw5 [17]

Hydrogen and oxygen will have completely new properties

6 0

2 years ago

How does the abundance of various isotopes affect the atomic mass?

eduard

solution:

The quoted atomic mass on the Periodic Table is the WEIGHTED average of the individual isotopic masses. The higher the isotopic percentage, the MORE that isotope will contribute to the isotopic mass. For this reason, most masses that are quoted on the Table are non-integral.

By way of example we could look to the hydrogen atom. The VAST majority of hydrogen atoms (in this universe) are the protium isotope. i.e. 1H, whose nuclei contain JUST the defining proton. There is a smaller percentage (>1%) of hydrogen atoms WITH one NEUTRON in their nuclei to give the deuterium isotope. i.e. 2H, and because this is relatively cheap, and easily incorporated into a molecule, deuterium labelling is routinely used in analysis.

And there is even a smaller percentage of hydrogen atoms with TWO NEUTRONS in their nuclei, to give the tritium isotope. i.e. 3H. The weighted average of the isotopic percentages gives $1.00794⋅g⋅mol^{−1}$

6 0

3 years ago