All categories

3 years ago

Is table salt and chalk a homogeneous or heterogeneous mixture?

2 answers:

8 0

Table salt is uniform in state when mixed with water as it dissolves so therefore table salt is homogeneous and chalk is heterogeneous because even grounded up it is still a cloudy substance and you would not be able to see through it :)

Dovator [93]3 years ago

3 0

The answer is heterogeneous

You might be interested in

Plz help i’m stuckkkk

scZoUnD [109]

Answer:

first

Explanation:

Assets = Equity + Liability. ...

Assets = Liabilities + Shareholder's Equity.

then ans will be in your feet it's east

3 0

2 years ago

When a new bond forms in a chemical reaction, what happens?

Kisachek [45]

The answer to this question would be A. Energy is released.

When a chemical bond is a form, the bond will either suck up energy or produce energy. So, to be precise the energy is not always released but also can be absorbed. In this case, the energy released number will be a minus.

Options B and C is definitely wrong since the bond is formed by an electron, it won't affects neutron/proton.
Option D might be true since the product is made of 2 or more atoms then it would seem larger. But the size of the actual atom won't be increased.

8 0

3 years ago

Read 2 more answers

6832 J of heat energy is applied to 5.9 mol of water. If the original temperature of the water was 18.60C, the final temperature

sineoko [7]

Answer: The final temperature of the water will be $34.0^0C$

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

$Q=m\times c\times \Delta T$

Q = Heat absorbed= $6832$ Joules

m= mass of water = $5.9mol\times 18g/mol=106.2g$

c = specific heat capacity = $4.184J/g^0C$

Initial temperature of the water = $T_i$ = $18.6^0C$

Final temperature of the water = $T_f$ = ?

Putting in the values, we get:

$6832=106.2\times 4.184\times (T_f-18.6)$

$T_f=34.0^0C$

The final temperature of the water will be $34.0^0C$

8 0

3 years ago

Why is publishing your results important in science?

aleksandr82 [10.1K]

Answer: A

Hope I helped

8 0

2 years ago

When 2,4-hexadiene is protonated, a resonance-stabilized secondary allylic carbocation is formed. Draw the curved arrow notation

NemiM [27]

Answer:see the image for the structure of the allylic carbocation

Explanation:

When 2,4-hexanediene is protonated at the 5-position as shown in the image, a carbonation is formed which can be stabilized by resonance. The positive charge can be found on carbon 4 or carbon 2 due to resonance of the allylic carbonation. The both structures are shown and electron movements were depicted using curved arrow notation in the structures shown in the image attached.

4 0

3 years ago