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Igoryamba
2 years ago
12

Calculate the density of oxygen, O2 , under each of the following conditions:

Chemistry
1 answer:
sdas [7]2 years ago
4 0

The density of oxygen, O2 , under each of the following conditions:

STP 1.00 atm and 20.0°C is 1.78 g/L.

<h3>What is the density of a substance?</h3>

Density is the ratio of mass and volume of a substance.

The density of oxygen under the given conditions is calculated as follows:

STP = standard temperature and pressure.

standard pressure = 1 atm pressure

standard temperature = 25°C

Volume of 1 mole of a gas at STP = 22.4 L/mol

Thus, 1 mole of O2 occupies the volume , V = 22.4 L/mol

Volume of oxygen at 20°C is calculated using:

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁

V₂ = 22.4 * 20/25

V₂ = 17.92

Hence;

density = 32 g/17.92

Density = 1.78 g/L

In conclusion, density is ratio of mass and volume.

Learn more about density at: brainly.com/question/952755

#SPJ1

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At 25°C, K = 0.090 for the following reaction. H2O(g) + Cl2O(g) equilibrium reaction arrow 2 HOCl(g) Calculate the concentration
wlad13 [49]

Answer:

  • [HOCl] = 0.00909 mol/liter
  • [H₂O] = 0.03901 mol/liter
  • [Cl₂O] = 0.02351 mol/liter

Explanation:

<u />

<u>1. Chemical reaction:</u>

H_2O(g)+Cl_2O(g)\rightleftharpoons 2 HOCl(g)

<u>2. Initial concentrations:</u>

i) 1.3 g H₂O

  • Number of moles = 1.3g / (18.015g/mol) = 0.07216 mol
  • Molarity, M = 0.07216 mol / 1.5 liter = 0.0481 mol/liter

ii) 2.2 g Cl₂O

  • Number of moles = 2.2 g/ (67.45 g/mol) = 0.0326 mol
  • Molarity = 0.0326mol / 1.5 liter = 0.0217 mol/liter

<u>3. ICE (Initial, Change, Equilibrium) table</u>

            H_2O(g)+Cl_2O(g)\rightleftharpoons 2 HOCl(g)

I            0.0481      0.0326            0

C              -x                 -x              +x

E          0.0481-x    0.0326-x         x

<u />

<u>4. Equilibrium expression</u>

       K_c=\dfrac{[HOCl]^2}{[H_2O].[Cl_2O]}

     0.09=\dfrac{x^2}{(0.0481-x)(0.0326-x)}

<u />

<u>5. Solve:</u>

            x^2=0.09(x-0.0481)(x-0.0326)\\\\0.91x^2+0.007263x-0.000141125=0

Use the quadatic formula:

x=\dfrac{-0.007263\pm \sqrt{(0.007263)^2-4(0.91)(-0.000141125)}}{2(0.91)}

The positive result is x = 0.00909

Thus the concentrations are:

  • [HOCl] = 0.00909 mol/liter
  • [H₂O] = 0.0481 - 0.00909 = 0.03901 mol/liter
  • [Cl₂O] = 0.0326 - 0.00909 = 0.02351 mol/liter

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Answer:

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Explanation:

hope this helps lol and have a great day

8 0
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Read 2 more answers
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