Answer:
alr 5x+11 and 2x-3
5x+11=16x
2x-3=-1x
Step-by-step explanation:
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Answer:
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Class 9
>>Maths
>>Quadrilaterals
>>Quadrilaterals and Their Various Types
>>In Fig. 6.43, if PQ PS, PQ∥ SR, SQR = 2
Question
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In Fig. 6.43, if PQ⊥PS,PQ∥SR,∠SQR=28
0
and ∠QRT=65
0
, then find the values of x and y.
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Solution
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Given, PQ⊥PS,PQ∥SR,∠SQR=28
∘
,∠QRT=65
∘
According to the question,
x+∠SQR=∠QRT (Alternate angles as QR is transversal.)
⇒x+28
∘
=65
∘
⇒x=37
∘
Also ∠QSR=x
⇒∠QSR=37
∘
Also ∠QRS+∠QRT=180
∘
(Linear pair)
⇒∠QRS+65
∘
=180
∘
⇒∠QRS=115
∘
Now, ∠P+∠Q+∠R+∠S=360
∘
(Sum of the angles in a quadrilateral.)
⇒90
∘
+65
∘
+115
∘
+∠S=360
∘
⇒270
∘
+y+∠QSR=360
∘
⇒270
∘
+y+37
∘
=360
∘
⇒307
∘
+y=360
∘
⇒y=53
∘
Step-by-step explanation:
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Answer: x = 156°
Step-by-step explanation:
So it is proven all triangles equal 180° and all straight angles are 180° so
85+71= 156
180-156=24°
but since you are trying to find x (to create the straight angle) and now know the other missing angle is 24°
180-24= 156
x=156°
Answer:
x = 16
Step-by-step explanation:
3(x+2)-x=38
Distribute
3x+6 -x = 38
Combine like terms
2x+6 = 38
Subtract 6 from each side
2x+6-6 = 38-6
2x = 32
Divide each side by 2
2x/2 = 32/2
x = 16
70 cm
ex:
100 cm in a meter
so you’d do 100-30 cm
and that equals 70 centimeters
