Answer:
mean of this demand distribution = 100
Step-by-step explanation:
To find the mean of this demand distribution;
Mean = Expected vale = E[x]
for discrete provability function,
we say E[x] = ∑(x.p(x))
x p(x) x.p(x)
10 0.1 1
30 0.4 12
60 0.4 24
90 0.7 63
∴ ∑(x.p(x)) = ( 1 + 12 + 24 + 63 )
∑(x.p(x)) = 100
Answer:
Step-by-step explanation:
g(t)=t^2 - t
f(x) = (1 + x)
g(f(x)) = f(x)^2 - f(x)
g(f(x)) = (x + 1)^2 - x - 1
g(f(0)) = (0 +1)^2 - x - 1
g(f(0)) = 1 - 1 - 1 = -1
================================
f(x) = 1 + x
f(g(t)) = 1 + g(t)
f(g(t)) = 1 + t^2 - t
f(g(0)) = 1 + 0 - 0
f(g(0)) = 1
The answer I'm getting is 0.
The vertex would be at (5,-2)
18/60 which is equal to 3/10
So you just need to put it into proportions which is blue to total. The total is 60 and there is 18 blue. Then you only need to simplify.
Given:
a square with an area of a² is enlarged to a square with an area of 25a².
The side length of the smaller square was changed when The side length was multiplied by 5.
Area = (1a)² = a²
Area = 1a * 5 = 5a ⇒ (5a)² = 25a²
