Our aim is to calculate the Radius so that to use the formula related to the area of a segment of a circle, that is: Aire of segment = Ф.R²/2
Let o be the center of the circle, AB the chord of 8 in subtending the arc f120°
Let OH be the altitude of triangle AOB. We know that a chord perpendicular to a radius bisects the chord in the middle. Hence AH = HB = 4 in
The triangle HOB is a semi equilateral triangle, so OH (facing 30°)=1/2 R. Now Pythagoras: OB² = OH² + 4²==> R² = (R/2)² + 16
R² = R²/4 +16. Solve for R ==> R =8/√3
OB² = OH² +
Answer:
x = 45°
Step-by-step explanation:
80° + 55° + x = 180°
135° + x = 180°
x = 45°
Answer:
i think A. 6 in
Step-by-step explanation:
because the lenght is diagram 3
Answer:
what are we solving?
Step-by-step explanation:
Answer: They are similar but not congruent.
Step-by-step explanation: hope this help
