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Ksenya-84 [330]
3 years ago
15

Two forces of 30 pounds and 40 pounds act upon a body, forming an acute angle with each other. The angle between the resultant a

nd the 30-pound force is 35degree 10'. Find, to the nearest ten minutes, the angle between the two given forces
Mathematics
1 answer:
tekilochka [14]3 years ago
8 0
Angles in the triangle are 
<span>35°10' </span>
<span>180° - A (with A = angle between the 2 forces) </span>
<span>A - 35°10' </span>

<span>40/sin35°10' = 30/sin(A-35°10') </span>
<span>sin(A-35.17) = 30sin35.17°/40 = 0.432 </span>

<span>A-35.17= 25.6 </span>
<span>A = 60.77° = 60°46' </span>
<span>60°50'</span>
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Answer:

y = 300

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Step-by-step explanation:

Esta pregunta parece incompleta, parece que acá tenemos un sistema de ecuaciones:

x + y = 500

10*x + 20*y = 8000

Estas ecuaciones tienen que resolverse en conjunto, y de acá sacaremos un par de puntos (x, y) que son solución para ambas ecuaciones.

El primer paso para resolver esto es aislar una variable en una de las ecuaciones, en este caso podemos aislar x en la primera ecuación y así obtener:

x = 500 - y.

Ahora podemos reemplazar eso en la segunda ecuación y obtener:

10*(500 - y) + 20*y = 8000.

Ahora resolvemos esto para y.

5000 - 10*y + 20*y = 8000

10*y = 8000 - 5000 = 3000

y = 3000/10 = 300.

Y sabíamos que:

x = 500 - y = 500 - 300 = 200

Entonces la solución es:

y = 300

x = 200

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How do I solve #7? do i add all the angles together like a normal triangle and make it equal to 180?
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y =  126

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