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skelet666 [1.2K]
3 years ago
15

Let f(x) = -5x - 4 and g(x) = 6x - 7. Find f(x) + g(x)

Mathematics
1 answer:
Fynjy0 [20]3 years ago
3 0
Simple...

if f(x)= -5x-4 and g(x)=6x-7

And you want f(x)+g(x)

then just add.....f(x)+g(x)

-5x-4+6x-7

1x-11

This is the answer to f(x)+g(x)=1x-11

Thus, your answer.
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the sum of four consecutive integers is 2174. what are the integers? (continuation) the smallest of four consecutive integers is
timofeeve [1]
The smallest of the four numbers is x.
Since the four numbers are consecutive, this means that each number is one more than the previous.
Therefore, the four numbers are:
x
x + 1
x+1 + 1 = x+2
x+2 + 1 = x+3

Now, we are given that the sum (s) of the four numbers is 2174
This means that:
s = x+x+1+x+2+x+3
s = 4x + 6

We are given that s = 2174. Substitute with s in the above equation and solve for x as follows:
2174 = 4x + 6
4x = 2174 - 6
4x = 2168
x = 2168 / 4
x = 542

Based on the above calculations, the four numbers are:
542, 543, 544 and 555

7 0
3 years ago
Read 2 more answers
Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and
zloy xaker [14]

Answer:

(0,0)   (4000,0) and (500,79)

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW

\frac{dW}{dt} = -0.02W + 0.00004RW

To solve this, we first equate \frac{dR}{dt} and \frac{dW}{dt} to 0.

So, we have:

0.09R(1 - 0.00025R) - 0.001RW = 0

-0.02W + 0.00004RW = 0

Factor out R in 0.09R(1 - 0.00025R) - 0.001RW = 0

R(0.09(1 - 0.00025R) - 0.001W) = 0

Split

R = 0   or 0.09(1 - 0.00025R) - 0.001W = 0

R = 0   or  0.09 - 2.25 * 10^{-5}R - 0.001W = 0

Factor out W in -0.02W + 0.00004RW = 0

W(-0.02 + 0.00004R) = 0

Split

W = 0 or -0.02 + 0.00004R = 0

Solve for R

-0.02 + 0.00004R = 0

0.00004R = 0.02

Make R the subject

R = \frac{0.02}{0.00004}

R = 500

When R = 500, we have:

0.09 - 2.25 * 10^{-5}R - 0.001W = 0

0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0

0.09 -0.01125 - 0.001W = 0

0.07875 - 0.001W = 0

Collect like terms

- 0.001W = -0.07875

Solve for W

W = \frac{-0.07875}{ - 0.001}

W = 78.75

W \approx 79

(R,W) \to (500,79)

When W = 0, we have:

0.09 - 2.25 * 10^{-5}R - 0.001W = 0

0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0

0.09 - 2.25 * 10^{-5}R = 0

Collect like terms

- 2.25 * 10^{-5}R = -0.09

Solve for R

R = \frac{-0.09}{- 2.25 * 10^{-5}}

R = 4000

So, we have:

(R,W) \to (4000,0)

When R =0, we have:

-0.02W + 0.00004RW = 0

-0.02W + 0.00004W*0 = 0

-0.02W + 0 = 0

-0.02W = 0

W=0

So, we have:

(R,W) \to (0,0)

Hence, the points of equilibrium are:

(0,0)   (4000,0) and (500,79)

4 0
3 years ago
What is the 11th term of the sequence<br> 1, 2, 4, 8, 16, ...?
iris [78.8K]

Answer:

1024

Step-by-step explanation:

16x2=32

32x2=64

64x2=128

128x2=256

256x2=512

512x2=1024

x= previous term multiplied by 2

hopefully this helps :)

5 0
3 years ago
WILL GIVE BRAINIEST TO ONLY THE FIRST ANSWER!! Find the sum of the first 150 terms in the sequence 20, 15, 10, 5...
enot [183]

Answer:

-450

Step-by-step explanation:

Say the first number is x to get the idea.

The first 150 terms are 150x - 5 * 150

15x - 750

300 - 750 = -450

7 0
4 years ago
Does anyone know what the y-int is please help
tester [92]
I’m pretty sure it’s 1
5 0
3 years ago
Read 2 more answers
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