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3 years ago

What is the amplitude of 1-sin 2πx/3? Please explain.

Mathematics

1 answer:

swat323 years ago

4 0

Answer:

a=-1

b= $\frac{2\pi }{3}$

c=0

d=0

Step-by-step explanation:

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Please help me with this ASAP!!!!!!

storchak [24]

Answer:

Which Question?

Step-by-step explanation:

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2 years ago

Courtney and Alan are conducting an experiment. Every time Courtney flips a fair two-sided coin, Alan rolls a six-sided die. Wha

Naily [24]

Answer:

I think the answer is D. 1/12

7 0

2 years ago

Read 2 more answers

Charlotte drives 64 mph for the first 3 hours of her trip and 92 mph for last 4 hours.

german

Answer:

80 mph

Step-by-step explanation:

$\boxed{\sf Distance=Speed \times Time}$

<u>First leg of trip</u>

Speed = 64 mph
Time = 3 hours

$\implies \sf Distance =64\times 3 = 192\:miles$

<u>Second leg of trip</u>

Speed = 92 mph
Time = 4 hours

$\implies \sf Distance=92 \times 4 = 368\:miles$

$\boxed{\sf Speed=\dfrac{Distance}{Time}}$

To find the average speed:

$\begin{aligned}\implies \sf Average\:speed & = \sf \dfrac{Total\:distance}{Total\:time}\\\\ & = \sf \dfrac{192+368}{3+4}\\\\& = \sf \dfrac{560}{7}\\\\ & = \sf 80\:mph\end{aligned}$

6 0

2 years ago

Read 2 more answers

This afternoon, Sara noticed that the number of the page assigned for homework is divisible by both 12

max2010maxim [7]

Answer:

Step-by-step explanation:

Well, 12/12=1, which I guess is the smallest number we can get, and 12 is divisible by 2 too.

7 0

3 years ago

A healthcare provider monitors the number of CAT scans performed each month in each of its clinics. The most recent year of data

Rasek [7]

Answer: a. 1.981 < μ < 2.18

b. Yes.

Step-by-step explanation:

A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.

First, we calculate mean of the sample:

$\overline{x}=\frac{\Sigma x}{n}$

$\overline{x}=\frac{2.31=2.09+...+1.97+2.02}{12}$

$\overline{x}=$ 2.08

Now, we estimate standard deviation:

$s=\sqrt{\frac{\Sigma (x-\overline{x})^{2}}{n-1} }$

$s=\sqrt{\frac{(2.31-2.08)^{2}+...+(2.02-2.08)^{2}}{11} }$

s = 0.1564

For t-score, we need to determine degree of freedom and $\frac{\alpha}{2}$ :

df = 12 - 1

df = 11

$\alpha$ = 1 - 0.95

α = 0.05

$\frac{\alpha}{2}=$ 0.025

Then, t-score is

$t_{11,0.025}$ = 2.201

The interval will be

$\overline{x}$ ± $t.\frac{s}{\sqrt{n} }$

2.08 ± $2.201\frac{0.1564}{\sqrt{12} }$

2.08 ± 0.099

The 95% two-sided CI on the mean is 1.981 < μ < 2.18.

B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.

8 0

3 years ago