Answer:
= a⁸/b⁻¹⁰
Step-by-step explanation:
Simplify the expression
(a^2b^-3/a^-2b^2)^2
= a⁴b⁻⁶/a⁻⁴b⁴
Using the law of indices
= a⁴⁻⁽⁻⁴⁾/b⁻⁶⁻⁴
= a⁴⁺⁴/b⁻¹⁰
= a⁸/b⁻¹⁰
We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:

Where
represents the number of objects/people in the set and
represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set


Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru
Answer:
c and d
Step-by-step explanation:
If you do 5*the ratio of ur mom then u will get Y which times ur dads ding dong get u f(x)= 758984327934792379427893.