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Triss [41]
3 years ago
12

Natasha bought a new CD player on Friday. It cost $72. On Monday, she found that the CD player was on sale. The sale price is $5

4. What percent of the original price was the sale price
Mathematics
1 answer:
Gekata [30.6K]3 years ago
8 0

Answer:

25 percent

Step-by-step explanation:

Find what percent of 72 is 54:

(x/100)*72=54

x - percent

x*(72/100)=54

x=54:0,72

x=75

which means the sale was 25%

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3 0
4 years ago
Pls help I’m been stuck
ziro4ka [17]

Answer:

ANSWER: ADC=82

bda = 144

(7x+34)+(9x+46)=144

16x+80=144

16x=64

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adc=82

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Help me plz i can't figure this out
zzz [600]

Answer:

C

Step-by-step explanation:

For C the y axis changes, add 5 to -3 and you get 2. Therefore 5 units away!

Hope this helps, good luck! :)

6 0
3 years ago
Which shows 63 factored into powers of prime numbers?   A. 9 • 7   B. 32 • 7   C. 33 • 7   D. 3 • 3 • 7
s2008m [1.1K]

Hi!

<h3>To find the prime factorization of a number, keep dividing by the smallest factor that goes into it. </h3>

63/3 = 21

21/3 = 7

7/7 = 1

<u>3 · 3 · 7 = 63</u>

<h2>The answer is D. 3 · 3 · 7 </h2>

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6 0
3 years ago
Read 2 more answers
Arrange the geometric series from least to greatest based on the value of their sums.
son4ous [18]

Answer:

80 < 93 < 121 < 127

Step-by-step explanation:

For a geometric series,

\sum_{t=1}^{n}a(r)^{t-1}

Formula to be used,

Sum of t terms of a geometric series = \frac{a(r^t-1)}{r-1}

Here t = number of terms

a = first term

r = common ratio

1). \sum_{t=1}^{5}3(2)^{t-1}

   First term of this series 'a' = 3

   Common ratio 'r' = 2

   Number of terms 't' = 5

   Therefore, sum of 5 terms of the series = \frac{3(2^5-1)}{(2-1)}

                                                                      = 93

2). \sum_{t=1}^{7}(2)^{t-1}

   First term 'a' = 1

   Common ratio 'r' = 2

   Number of terms 't' = 7

   Sum of 7 terms of this series = \frac{1(2^7-1)}{(2-1)}

                                                    = 127

3). \sum_{t=1}^{5}(3)^{t-1}

    First term 'a' = 1

    Common ratio 'r' = 3

    Number of terms 't' = 5

   Therefore, sum of 5 terms = \frac{1(3^5-1)}{3-1}

                                                 = 121

4). \sum_{t=1}^{4}2(3)^{t-1}

    First term 'a' = 2

    Common ratio 'r' = 3

    Number of terms 't' = 4

    Therefore, sum of 4 terms of the series = \frac{2(3^4-1)}{3-1}

                                                                       = 80

    80 < 93 < 121 < 127 will be the answer.

4 0
3 years ago
Read 2 more answers
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