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dybincka [34]
3 years ago
10

Find the length , in centimeters , if the width is 48 1. 10 centimeters

Mathematics
1 answer:
ruslelena [56]3 years ago
6 0
It is 40 becuase points and due
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Read 2 more answers
What is the interquartile range of the sequence 5,5,8,8,13,14,16,16,19,22,23,27,31 ?
Romashka-Z-Leto [24]

Answer:

The Interquartile range is 10.

Step-by-step explanation:

First, we will need to find the mean, the mean of this sequence is 16, you will now need to find quartile 1 and quartile 3. Quartile 1 is 13, and quartile 3 is 23. Lastly, subtract Quartile 3 and Quartile 1 will be the answer.

So, 23-13=10

The Answer will be 10, the interquartile range is 10.

Hope this helps!

4 0
3 years ago
3y-2x=-9 put equation of line in slope intercept form
Allushta [10]

Answer:

Step-by-step explanation:

y=2/3x-3

4 0
1 year ago
I need help please please I appreciate it! ):
telo118 [61]

Answer:

!. Scale factor = 5

2. Scale factor = \frac{1}{5}

Step-by-step explanation:

scale = \frac{length in drawing}{actual length}

1. To increase the numbers, let the scale factor be \frac{5}{1} = 5. So that;

0.05 x 5 = 0.25

\frac{1}{2} x 5 = 0.5 x 5 = 2.50

7 x 5 = 35.00

13 x 5 = 65.00

25 x 5 = 125.00

102 x 5 = 510.00

2. To decrease the numbers, let the scale factor be \frac{1}{5}. So that;

0.05 x \frac{1}{5} = 0.01

\frac{1}{2} x \frac{1}{5} = 0.5 x \frac{1}{5} = 0.10

7 x \frac{1}{5} = 1.40

13 x \frac{1}{5} = 2.60

25 x \frac{1}{5} = 5.00

102 x \frac{1}{5} = 20.40

6 0
3 years ago
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