For a family gathering, Brittany made 5 meat loaves using 9 pounds of ground beef. How many pounds in each meat loaf?

2 answers:

5 0

There would be 45 pounds of meat in each loaf. The way I did it was since its asking you how many pounds in EACH meat loaf, the word each means to multiply. So I just multiplied 5 and 9 and got 45.

Anni [7]3 years ago

3 0

9/5 pounds in each. You are trying to solve for pounds per meatloaf, thus you would have the setup:
pounds / # of meatloafs which is 9/5

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Evaluate the surface integral ∫sf⋅ ds where f=⟨2x,−3z,3y⟩ and s is the part of the sphere x2 y2 z2=16 in the first octant, with

skad [1K]

Parameterize S by the vector function

$\vec s(u,v) = \left\langle 4 \cos(u) \sin(v), 4 \sin(u) \sin(v), 4 \cos(v) \right\rangle$

with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2.

Compute the outward-pointing normal vector to S :

$\vec n = \dfrac{\partial\vec s}{\partial v} \times \dfrac{\partial \vec s}{\partial u} = \left\langle 16 \cos(u) \sin^2(v), 16 \sin(u) \sin^2(v), 16 \cos(v) \sin(v) \right\rangle$

The integral of the field over S is then

$\displaystyle \iint_S \vec f \cdot d\vec s = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \vec f(\vec s) \cdot \vec n \, du \, dv$

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