Answer:
x = 3/2
The axis of symmetry is located at the vertex,
which is the also the highest point in this problem...
the x component of the vertex can be calculated as -b/2a = -48/-32 = 24/16 = 6/4 = 3/2
x = 3/2
Step-by-step explanation:
Not exactly
2/10 = .2
1/4 = .25
1/4 is 0.05 bigger than 2/10
F(4) value is 6.
I believe it would work like this:
f(x) is being turned into f(4), so 4 would equal x. Put 4 into the equation 3x-6, and you get 12-6, which gives you 6. So the value of f(4) is 6. I hope this helps!
Answer:
20
Step-by-step explanation:
3/8* 32= 12
32-12=20
12 Girls
20 Boys
Answer:
Roots are not real
Step-by-step explanation:
To prove : The roots of x^2 +(1-k)x+k-3=0x
2
+(1−k)x+k−3=0 are real for all real values of k ?
Solution :
The roots are real when discriminant is greater than equal to zero.
i.e. b^2-4ac\geq 0b
2
−4ac≥0
The quadratic equation x^2 +(1-k)x+k-3=0x
2
+(1−k)x+k−3=0
Here, a=1, b=1-k and c=k-3
Substitute the values,
We find the discriminant,
D=(1-k)^2-4(1)(k-3)D=(1−k)
2
−4(1)(k−3)
D=1+k^2-2k-4k+12D=1+k
2
−2k−4k+12
D=k^2-6k+13D=k
2
−6k+13
D=(k-(3+2i))(k+(3+2i))D=(k−(3+2i))(k+(3+2i))
For roots to be real, D ≥ 0
But the roots are imaginary therefore the roots of the given equation are not real for any value of k.
