Answer:
4.23076923077
Step-by-step explanation:
Answer:
About 41.5%
Step-by-step explanation:
<em>Given:</em>
<em>A bowl has 8 green grapes and 15 red grapes. Henry randomly chooses a grape, eats it, and then chooses another grape. </em>
<em>To Find:</em>
<em>What is the probability that both grapes are red?</em>
<em>Answer choices:</em>
<em>about 39.7% </em>
<em>about 41.5%</em>
<em> about 42.5% </em>
<em>about 44.5%</em>
<em>Solution:</em>
<em>Since, there are 8 green grapes and 15 red grapes, the total number of grapes is 23 . </em>
<em>As the red grapes are 15.. </em>
<em>Thus, </em>
<em>The probability of choosing a red grape the first time is 15/23.</em>
<em>Because out of the total 23 grapes only 15 were red grape.</em>
<em> The probability of choosing the red grape the second time will be 14/22. Because the number of red grapes has already decreased by one and so is the total number of grapes after first choice</em>
<em>Hence, the probability of choosing or eating two red grapes will be :</em>
<em>15/23×14/22 </em>
<em>=105/253 </em>
<em>=0.415</em>
<em>= 41.5% </em>
<em>Therefore, the probability that both grapes are red is about 41.5%</em>
<u><em>Kavinsky</em></u>
Wow… how is this a question? .-.
The answer is: " 8 " .
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Explanation:
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Let "x" represent the "original number".
2(x - 3) = 6 + (1/2)x ; Solve for "x" ;
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Multiple the ENTIRE EQUATION (both sides) by "2" ; to get rid of the fraction:
2*{2(x - 3) = 6 + (1/2)x} ;
to get:
4(x - 3) = 12 + x ;
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Let us expand the "left-hand side" of the equation:
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Note the "distributive property of multiplication" :
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a(b - c) = ab - ac ;
a(b +c) = ab + ac ;
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So; "4(x - 3)" = 4*x - 4*3 = 4x - 12 ;
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Rewrite the equation:
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4x - 12 = 12 + x ;
Subtract "x" from EACH side of the equation; and Add "12" to EACH SIDE OF THE EQUATION;
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4x - 12 - x + 12 = 12 + x - x + 12 ;
to get:
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3x = 24 ;
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Now, divide EACH side of the equation by "3" ; to isolate "x" on one side of the equation; and to solve for "x" ;
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3x/3 = 24/3 ;
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x = 8 .
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Associativity means
(A+B)+C=A+(B+C)=A+B+C
Substitute A=9, B=8, C=32 to apply to this problem.
