The roots of the given polynomial function is {-4, -2, -3 + 2i, -3 - 2i}.
<h3>How to get the roots of the polynomial?</h3>
Here we have the polynomial function:

So we just need to find the roots of the two quadratic functions, to do that, we use Bhaskara's formula.
For the first one, we have:

So the two solutions are:
x = (-6 - 2)/2 = -4
x = (-6 + 2)/2 = -2
For the second quadratic we have:

So the two solutions are:
x = -3 + 2i
x = -3 - 2i
Finally, the list is:
{-4, -2, -3 + 2i, -3 - 2i}
If you want to learn more about polynomials:
brainly.com/question/4142886
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