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2 years ago

What is the value of x?

Mathematics

2 answers:

elena-14-01-66 [18.8K]2 years ago

8 0

29 degree I did the same test

Darya [45]2 years ago

4 0

The value of x is 29 degrees

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it is $14.75 ....................

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2 years ago

4x+3x-5x-5+5x+5x-x3+x2-8x+2x+7-5x

Yuri [45]

1.) Group like terms: 4x+3x-5x+5x+5x-3x+2x-8x+2x-5x-5+7

2.) Add similar elements: = 4x+3x-5x+5x+5x-3x+2x-8x+2x-5x=0

3.) =-5+7

4.) Add/Subtract the numbers: -5 + 7 = 2

<u>Your Answer: 2</u>

5 0

3 years ago

SOLUTION We observe that f '(x) = -1 / (1 + x2) and find the required series by integrating the power series for -1 / (1 + x2).

Ann [662]

Answer:

Required series is:

$\int{\frac{-1}{1+x^{2}} \, dx =-x+\frac{x^{3}}{3}-\frac{x^{5}}{5}+\frac{x^{7}}{7}+.....$

Step-by-step explanation:

Given that

$f'(x) = -\frac{1}{1 + x^{2}}$ ---(1)

We know that:

$\frac{d}{dx}(tan^{-1}x)=\frac{1}{1+x^{2}}$ ---(2)

Comparing (1) and (2)

$f'(x)=-(tan^{-1}x)$ ---- (3)

Using power series expansion for $tan^{-1}x$

$f'(x)=-tan^{-1}x=-\int {\frac{1}{1+x^{2}} \, dx$

$= -\int{ \sum\limits^{ \infty}_{n=0} (-1)^{n}x^{2n}} \, dx$

$= -\sum{ \int\limits^{ \infty}_{n=0} (-1)^{n}x^{2n}} \, dx$

$=-[c+\sum\limits^{ \infty}_{n=0} (-1)^{n}\frac{x^{2n+1}}{2n+1}]$

$=C+\sum\limits^{ \infty}_{n=0} (-1)^{n+1}\frac{x^{2n+1}}{2n+1}$

$=C-x+\frac{x^{3}}{3}-\frac{x^{5}}{5}+\frac{x^{7}}{7}+.....$

$tan^{-1}(0)=0 \implies C=0$

Hence,

$\int{\frac{-1}{1+x^{2}} \, dx =-x+\frac{x^{3}}{3}-\frac{x^{5}}{5}+\frac{x^{7}}{7}+.....$

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3 years ago

What should be the first step to solve the equation? 2x + 9(x - 1) = 8(2x + 2) - 5

MAXImum [283]

Step-by-step explanation:

the answer is b

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2 years ago

How do you know that a =6 is a solution to a+5=11?

Gre4nikov [31]

a + 5 = 11

You need to isolate the variable by subtracting from both sides

a + 5 - 5 = 11 - 5

a = 6

The Addition/Subtraction Property of Equality states that if you add or subtract the same number to both sides of an equation the two sides still remain equal.

:))

4 0

2 years ago

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