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tensa zangetsu [6.8K]

4 years ago

10

Is F(x)=2 x 3^a exponetial growth or decay

1 answer:

sukhopar [10]4 years ago

4 0

The answer is exponential growth because it goes up in value

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Which expression is equivalent to <br><br> 2y5z10<br> 2xy2z3<br> 6y5z10<br> 6xy2z3

pantera1 [17]

Answer:

it is 2xy^2z^3 if the number under the square root(5)√(32x^(5)y^(10)z^(15))

Step-by-step explanation:

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3 years ago

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Kelly sleeps 8 hours a day. If an equation were written to show the number of hours Kelly has slept for any given number of days

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<span>C. number of hours slept</span>

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Use the binomial expression (p+q)^n to calculate a binomial distribution with n=5 and p=0.3.(Show all steps)

Helen [10]

Answer:

The binomial in expanded form is $(0.3 + q)^{5} = \frac{243}{100000} + \frac{81}{2000}\cdot q + \frac{27}{100}\cdot q^{2} + \frac{9}{10} \cdot q^{3} + \frac{3}{2}\cdot q^{4} + q^{5}$ .

Step-by-step explanation:

The Binomial Theorem states that a binomial of the form $(a + b)^{n}$ can be expanded by using the following identity:

$(a + b)^{n} = \Sigma \limits^{n}_{k = 0}\,\frac{n!}{k!\cdot (n-k)!}\cdot a^{n-k}\cdot b^{k}$ (1)

If we know that $a = p = 0.3$ and $n = 5$ , then the expanded form of the binomial is:

$(p+q)^{n} = \frac{243}{100000} + 5\cdot \left(\frac{81}{10000} \right)\cdot q + 10\cdot \left(\frac{27}{1000})\cdot q^{2} + 10\cdot \left(\frac{9}{100} \right)\cdot q^{3} + 5\cdot \left(\frac{3}{10} \right)\cdot q^{4} + q^{5}$

$(0.3 + q)^{5} = \frac{243}{100000} + \frac{81}{2000}\cdot q + \frac{27}{100}\cdot q^{2} + \frac{9}{10} \cdot q^{3} + \frac{3}{2}\cdot q^{4} + q^{5}$

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3 years ago

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Answer: what am I suppose to do with that?

Step-by-step explanation:

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3 years ago

May anyone please help?

allsm [11]

I think it’s yes but I may be wrong

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