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jek_recluse [69]
3 years ago
13

Question 3 -

Mathematics
1 answer:
mario62 [17]3 years ago
5 0
No, because for example 2+2 is 4 but if you mean -2+2 that is 0



Hope this is helpful
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find a model for simple harmonic motion if the position at t = 0 is 6, the amplitude is 6 centimeters, and the period is 4 secon
Y_Kistochka [10]

Answer:

y = 6cos(π/2)t

Step-by-step explanation:

Given in the question that,

in a simple harmonic motion in which

at t=0 the amplitude is 6 cm, so the simple harmonic motion will be in cosine form. As in case of sine function, the value of function at t=0 is 0.  

And,

the period is given as 4 sec

We know that model equation of simple harmonic motion is

<h3>y = a. cosb(t + c) + d</h3>

here,

a is amplitude

c is Horizontal shift or phase shift

d is Vertical shift

<h3>Step1</h3><h3>Find b</h3>

Period = 2 π / b

4 = 2π / b

b = 2π/4

b = 1π/2

<h3>Step2</h3><h3>Find shifts</h3>

Horizontal and vertical shifts are 0.

So, c = 0 and d = 0

<h3>Step3</h3><h3>Plug those values in the above in the equation</h3>

y = 6cos π/2 (t + 0) + 0

y = 6cos(π/2)t

4 0
4 years ago
HELPP!!<br> Solve for n. What does n equal in this equation. n-3 = 8
dedylja [7]

Answer:

11. n=11.

Step-by-step explanation:

11 - 3 = 8

Hope this helps. Have a good day!

8 0
3 years ago
Read 2 more answers
Rackham Graduate School has 8,000 students (5,000 PhD students and 3,000 masters stu- dents). The Rackham Student Government Exe
Free_Kalibri [48]

Answer:

a) 8,000!/(8000 - 4)! ways

b) 15,000,000 + 7998!/(7998 - 2)! ways

c) 5,000 + 7,999!/(7,999- 3)! ways

d) 3,000 + 7,999!/(7,999- 3)! ways

Step-by-step explanation:

The number of students at Rackham Graduate School = 8,000 students

The number of PhD students = 5,000

The number of masters students = 3,000

The number of student members of the Rackham Student Government Executive Board = 4 students

a) The number of ways there are to choose the Exec Board from all Rackham students = The number of ways to choose 4 students from 8,000 = 8,000!/(8000 - 4)!

b) The number of ways of having one Master student in the board = 3,000 ways

The number of ways of having one PhD student in the board after selecting a masters student = 5,000 ways

The number of ways of selecting the remaining 2 members =

7998!/(7998 - 2)!

The total number of ways of selecting at least one masters and one PhD in the board is therefore equal to 5,000 × 3,000 + 7998!/(7998 - 2)! ways

c) The number of ways of choosing the VP position as PhD = 5,000 ways

The number of ways of choosing the other three members = 7,999!/(8000 - 3)!

Therefore, the total number of ways = 5,000 + 7,999!/(7,999- 3)! ways

d) The number of ways of choosing a masters student as the VP position = 3,000 ways

The number of ways of choosing the other three members = 7,999!/(8000 - 3)!

Therefore, the total number of ways = 3,000 + 7,999!/(7,999- 3)! ways

8 0
3 years ago
What does 2.65× =265
kifflom [539]

Answer:

100

Step-by-step explanation:

You take 265 and divide it by 2.65

4 0
3 years ago
SOLVE THIS PROBLEM ASAP
inna [77]

Answer:

6,6

There are 8 spaces in bettween  point a and b so 8/2 = 4 so 4 up from point a is 6,6

Step-by-step explanation:

8 0
3 years ago
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