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geniusboy [140]

4 years ago

15

Julia studied math for three one third hours during the 4 days before her last math test. What was the average amount of time sh

e studied each day?

1 answer:

butalik [34]4 years ago

8 0

She studied for 1 hour or 60 minutes.

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What three factors were used to create this product game board 4 6 9 14 49

notsponge [240]

Look at the factors in the 5 numbers. there are 3 factors, and each number is the product of 2 of them (or 1 of them, twice). There is one "pair" missing. Hope this helps!!!

5 0

3 years ago

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There is only one angle measure , ∡JHF , which is 34 degrees . I have to find the measure of angle ∡FJH .

Minchanka [31]

the assumption here being that both lines JH and FH are tangent lines to the circle, if that's the case the external angle of 34° is the angle made by the equal tangents, meaning the triangle is an isosceles with twin sides.

In an isosceles triangle the twin sides make also twin angles, so the angles at J and F are twins, and they'd be 180° - 34° = 146° total, since they're twins, each one takes half, or 73°.

5 0

3 years ago

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What is the value of y?

Romashka [77]

Answer:

y=42

Step-by-step explanation:

y+48+90=180

y=180-138

y=42

7 0

4 years ago

Brian had 42 class fair tickets to sell. He sold 5/6 of the tickets. How many tickets did Brian sell?

Hunter-Best [27]

Answer:

35

Step-by-step explanation:

8 0

3 years ago

The table displays the frequency of scores for a calculus class on an exam. The mean of the exam scores is 3.5. Score 1 2 3 4 5

vladimir1956 [14]

Answer:

f=11

Mode=4

Median=4

Explanation:

We are given that

a.Mean of the exam score, $\bar x$ =3.5

Score(x) frequency C.F

1 1 1

2 3 4

3 f 15(4+f=4+11)

4 13 28

5 4 32

$\sum f_i=1+3+f+13+4=21+f$

$\sum f_ix_i=1(1)+2(3)+3(f)+4(13)+5(4)=1+6+3f+52+20=79+3f$

$(\bar x)=\frac{\sum f_ix_i}{\sum f_i}$

Using the formula

$3.5=\frac{79+3f}{21+f}$

$73.5+3.5f=79+3f$

$3.5f-3f=79-73.5$

$0.5f=5.5$

$f=\frac{5.5}{0.5}=11$

b.Mode:The number which is repeat most times .

4 repeat most times

Hence, mode of all exam scores=4

N=32

N is even

$Median=\frac{(\frac{n}{2})^{th}+(\frac{n}{2}+1)^{th}}{2}$

Median= $\frac{16th+17th}{2}=\frac{4+4}{2}=\frac{8}{2}=4$

7 0

4 years ago