Answer:
there are two complex roots
Step-by-step explanation:
Recall that for a quadratic equation
y = ax² + bx + c
the solution given by the quadratic formula is
x = ( -b ± √discriminant) / 2a
if the discriminant is negative, the radical term will become √ (negative number), which we know gives complex solutions. Hence we can eliminate real roots as possible answers.
Also notice that the "±" sign in the quadratic formula means that you will get 2 possible solutions:
x = ( -b + √discriminant) / 2a
or
x = ( -b - √discriminant) / 2a
Hence we know we will get 2 solutions.
Combining our findings, we can conclude that if the discriminant is negative, we will get 2 complex roots.
