so we have a pentagon, namely a polygon with PENTA, 5 sides
Check the picture below.
The given expression is
We just have to divide by 2
<h2>Hence, the solution is all real numbers less than 10.</h2>
I am going to explain this using the substitution method, considering it appears to be the best in this situation.
We know (from the bottom equation) that y can equal 3x+20. Using this knowledge, we substitute the y in the top equation for 3x+20. Now, we have an equation that looks like this:
3x+20=x^2+2x
Now we need to move x to one side and then do some radicals (square roots).
Subtract the 2x on the right (since it is smaller, negatives = NONONO), which will give you
x+20=x^2
Now, we take the square root of both sides to get
rad(x+20)=x
Now we have to simplify. 20 doesn't have a square root, but 4 goes into 20, and 4 has a square root of 2. This now becomes
2rad(x+5)
This doesn't simplify any further... we have a problem... no way to isolate x as far as my knowledge goes... Sorry, can't help you any further than that, but another person or your teacher might be able to. R.I.P...
Hello,
aPb=b*(b-1)*(b-2)*....*(b-a+1) / a!
3P5=5*4*3/(3*2*1)=10
If we name the number of the employers 1,2,3,4,5
Here are the choices:
123,124,125,134,135,145,234,235,245,345 (total 10 choices)
Answer:
π(12.1)²
Step-by-step explanation:
12.1 is the radius
Formula for base = πr²
= π(12.1)²