Let's say a = number of ordered soups, b = number of ordered sandwiches.
Then 4.5a + 7.75b = 113.50, and a and b are integers between 0 and 18 inclusive.
How do we tackle this? If all ordered soup, the cost would be $81, so we'll have at least 4 sandwiches. If all ordered sandwich, the cost would be $139.5, so at most 15 sandwiches were ordered. You also know an even number of sandwiches was ordered, to let the price end at 50 cent.
If you brute-force from 4,6,8,10,12 to 14 sandwiches, you find the answer at 10 sandwiches and 8 soups.
10*7.75 + 8*4.50 = 113.50
Answer:The correct answer is D-x/2=45; x=90
Explanation: I just took the test and got a 100%
It is B.Scale factor=New length/old length=8/2=4
Answer:
2a^4 / b^5
Step-by-step explanation:
(2a^2 / b) x ( a / b^2) ^2
= (2a^2 / b) x (a^2 / b^4)
= 2a^4 / b^5
(p.s if you are not gonna do it don't say "no thanks" and leech off this poor man's points)
