The formula would be something like, P×h+(B × 2). Hope this helps.
Answer: 0.03538944
Step-by-step explanation:
Given, The accuracy of missile = 96%
i.e. The probability that it will hit the shot = 0.96
Probability of missing the shot = 1-0.96= 0.04
Now, each missile is independent of other.
Therefore, the probability only the second one misses = (probability that first will hit the shot) x (probability that second one misses ) x (probability that third will hit the shot)x (probability that fourth will hit the shot)
Thus, the probability only the second one misses is
Hence, the required probability = 0.03538944
There are 62.9 students and 11.1 teachers.
Weird, I know. But my math is bullet-proof.
first solve for the perimeter of the rectangle
2w + 2l = 42
since the length of the rectangle is twice as long as the length and width of the square
2w = l
solve using substitution
2w + 2(2w) = 42
2w + 4w = 42
6w = 42
w = 7
are is length x width. a square has the same length and width
7 x 7 = 49
the area of one square is 49
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