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Vlad [161]
3 years ago
9

The sum of 5 consecutive numbers is 135

Mathematics
1 answer:
enot [183]3 years ago
6 0
27+27+27+27+27 is 135
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What’s the answer? Pls help soon
Vilka [71]
You get this or no??
6 0
3 years ago
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7. y-2 = (x+3)<br> 4<br> 2<br> X<br> - TO<br> 12<br> 4
drek231 [11]

Answer:

y = -24 + -2x + 2x2

Step-by-step explanation:

Simplifying:

y = 2(x + 3)(x + -4)

reorder the terms:

y = 2(3 + x)(x + -4)

multiply (3 + x) * (-4 + x)

y = 2(3(-4 + x) + x(-4 + x))

y = 2((-4 * 3 + x * 3) + x(-4 + x))

y = 2((-12 + 3x) + x(-4 + x))

y = 2(-12 + 3x + (-4 * x + x * x))

y = 2(-12 + 3x + (-4x + x2))

Combine like terms  3x + -4x = -1x

y = 2(-12 + -1x + x2)

y = (-12 * 2 + -1x * 2 + x2 * 2)

y = (-24 + -2x + 2x2)

Solving:

y = -24 + -2x + 2x2

solving for variable 'y'

Move all terms containing y to the left, all other terms to the right.

Simplifying:

y = -24 + -2x + 2x2

8 0
3 years ago
Jack took a test and got 13 out of 17 points. He took a make-up test and got 12 out of 15 points.
blagie [28]

Answer:

4.6

Step-by-step explanation:

The answer is 4.6%, hope it helps! sorry if wrong!

3 0
3 years ago
Solve the system of equations by graphing: 2x + 3y = 2 6x + 18y = 9
cluponka [151]
The answer is  A: x=1/2 , y= 1/3

Solve the following system:
{2 x + 3 y = 2 | (equation 1)
{6 x + 18 y = 9 | (equation 2)

Swap equation 1 with equation 2:
{6 x + 18 y = 9 | (equation 1)
{2 x + 3 y = 2 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:
{6 x + 18 y = 9 | (equation 1)
{0 x - 3 y = -1 | (equation 2)

Divide equation 1 by 3:
{2 x + 6 y = 3 | (equation 1)
{0 x - 3 y = -1 | (equation 2)

Multiply equation 2 by -1:
{2 x + 6 y = 3 | (equation 1)
{0 x+3 y = 1 | (equation 2)

Divide equation 2 by 3:
{2 x + 6 y = 3 | (equation 1)
{0 x+y = 1/3 | (equation 2)

Subtract 6 × (equation 2) from equation 1:
{2 x+0 y = 1 | (equation 1)
v0 x+y = 1/3 | (equation 2)

Divide equation 1 by 2:
{x+0 y = 1/2 | (equation 1)
v0 x+y = 1/3 | (equation 2)

Collect results:
Answer:  {x = 1/2, y = 1/3

7 0
3 years ago
Quadrilateral ABCD is reflected across the x -axis. What are the coordinates of quadrilateral A'B'C'D'? A. A' (5, –5), B' (1, –5
Yuki888 [10]

Answer:

=76559

Step-by-step explanation:

foggy

5 0
3 years ago
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