Answer:
see the attached
Step-by-step explanation:
The total cost of Kaylee's purchases will be the sum of products of the number bought and the cost of the item bought. She wants this total to be at most $20. In math terms, where x and y represent songs and TV episodes, the inequalities describing the scenario are ...
- 1.29x +2.99y ≤ 20
- x ≥ 0
- y ≥ 4
The attached graph shows a plot of this set of inequalities with the feasible region shaded red. The combinations of songs and TV episodes Kaylee can afford are shown by the coordinates of the red dots in the feasible region.
According to the "special," if Kaylee buys 6 songs (and 4 TV episodes), she will get a 7th song free. That is, the "special" means point (6, 4) becomes (7, 4) if there is a 7th song that Kaylee wants.
Answer:
16.1 cm (nearest tenth)
Step-by-step explanation:
<u>Pythagoras’ Theorem</u>
(where a and b are the legs, and c is the hypotenuse, of a right triangle)
Given:
Substitute the given values into the formula and solve for c:
Answer:
Crafts books: 7
Cookbooks: 13
Step-by-step explanation:
Let x be the crafts book
Let y be the cookbooks
Solve for x:
- Plug x and y in: x + y = 20
- Re-write: y = x + 6
- Plug in x + 6 instead of y: x + x + 6 = 20
- Combine like terms: 2x + 6 = 20
- Subtract 6 from each side, so it now looks like this: 2x = 14
- Divide each side by 2 to cancel out the 2 next to x. It should now look like this: x = 7
Solve for y:
- Re-use an equation from above: y = x + 6
- Plug in the value of x: y = 7 + 6
- 7 + 6 = 13
- So, y = 13
I hope this helps!
<span>draw out a triangle and then create three boxes inside by drawing a T. In each of the boxes you've created you need to put one of the letters from the equation. The equation you currently have is F= m*a. To rearrange this equation put the m and the a into the bottom boxes and the F above. Because there is a vertical line between the m and the a, this means you times them. If there is a horizonal line between two letters you divide them. So to find a, you must divide F by m. </span>
