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Veseljchak [2.6K]
3 years ago
8

In a pair of complementary angles, the measurement of the larger angle is three times that of the smaller angle. Find the measur

ements of the two angles.
Mathematics
1 answer:
gayaneshka [121]3 years ago
8 0

Answer:

idkjrjejdjjdjdjdjfjdjfhjdjdhd

Step-by-step explanation:

idkjsjdjdjdjdjdjdjdjdjdjdjdjjfdjjr

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I’m struggling to answer this question on my test, can someone explain it to me?
Flauer [41]
Correct answer is Option A: 18/48 = 21/56

You’ll have to divide the numerator by the denominator of each fraction to see whether they have the same quotient:

18/48 = 0.375
21/56 = 0.375


The other options are not proportional.

B) 20/28 = 15/18:

20/28 = 0.714
15/18 = 0.833

Thus, 20/28 ≠ 15/18

C). 3/5 = 13/10
3/5 = 0.6
13/10 = 1.3

Hence, 3/5 ≠ 13/10

D) 7/10 = 10/7
7/10 = 0.7
10/7 = 1.43

Thus, 7/10 ≠ 10/7

These solutions prove that the correct answer is A) 18/48 = 21/56

Please mark my answers as the Briainliest if you find my explanations helpful :)
4 0
3 years ago
Find the value of x in the following figure
dedylja [7]
I think it’s 34 hope this helps
8 0
3 years ago
Read 2 more answers
a regular hexagonal nut of side 1 cm and length 3 cm with a central hole of diameter 1 cm. 3 cm 1 cm 1 cm. Calculate the volume
Bogdan [553]

Answer:

  5.44 cm³

Step-by-step explanation:

The volume of the hexagonal nut can be found by multiplying the area of the end face by the length of the nut. The end face area is the difference between the area of the hexagon and the area of the hole.

The area of a hexagon with side length s is given by ...

  A = (3/2)√3·s²

For s=1 cm, the area is ...

  A = (3/2)√3(1 cm)² = (3/2)√3 cm²

__

The area of a circle is given by ...

  A = πr²

The radius of a circle with diameter 1 cm is 0.5 cm. Then the area of the hole is ...

  A = π(0.5 cm)² = 0.25π cm²

__

The volume is the face area multiplied by the length, so is ...

  V = Bh = ((3/2)√3 -0.25π)(3) . . . . . cm³

  V = (9/2)√3 -0.75π cm³ ≈ 5.44 cm³

The volume of the metal is about 5.44 cm³.

5 0
3 years ago
-4x² – 26 + 7x – 6x² + 10 -12x =
finlep [7]
Hereeeee -10x ^2 -5x -16
3 0
3 years ago
Read 2 more answers
The coordinates of the vertices of AJKL are J(-5, -1), K(0, 1), and L(2, -5).
dalvyx [7]

We need slope of all lines ?

  • J(-5,-1)
  • K(0,1)
  • L(2,-5)

Slope of JK:-

\\ \sf\longmapsto m=\dfrac{1+1}{0+5}=\dfrac{2}{5}

Slope of KL:-

\\ \sf\longmapsto m=\dfrac{-5-1}{2-0}=\dfrac{-6}{0}=-3

Slope of JL

\\ \sf\longmapsto m=\dfrac{-5-1}{2+5}=\dfrac{-6}{7}

7 0
2 years ago
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