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Julli [10]
3 years ago
10

A and B are complementary to each other. If m∠A = 26° + x and m∠B = 38° + x, what is the value of x?

Mathematics
1 answer:
Zigmanuir [339]3 years ago
5 0

A. 13

Step-by-step explanation:

What we are given....

∠A = 26° + x

∠B = 38° + x

∠A and ∠B are complementary

If complementary angles add up to equal 90° and ∠A and ∠B are complementary to each other

Then 26 + x + 38 + x = 90

                      ^ ( Note that we just created an equation that we can use to                              solve for x )

Now its just basic algebra

26 + x + 38 + x = 90

step 1 combine like terms

26 + 38 = 64

x + x = 2x

we now have 64 + 2x = 90

step 2 subtract 64 from each side

64 - 64 cancels out

90 - 64 = 26

we now have 26 = 2x

step 3 divide each side by 2

26 / 2 = 13

2x / 2 = x

we're left with x = 13

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Rearranging literal equations ASAP NEED HELP
Tju [1.3M]

When we look at this thing for the first time, it looks like it's going to be a dog of a bear to solve, because 'q' is buried inside a squared term and a cubed term.

But this is why it's so important to learn that in math, you DON't immediately ignite your hair and go running around in circles as soon as you see the problem.  The first thing you have to do <u>every</u> time is sit still, look at the problem, breathe air, and switch your brain into the 'ON' position.

Look at that big ugly fraction in the equation.  Can it be simplified ? You betcha it can ! The quantity (q+r) is a factor of the numerator and denominator, so we can do some canceling.

Divide the top and the bottom of the fraction by (q+r)², and then the problem says . . .

<em>p = (q+r)/12  + 4r</em>

which is MUCH easier to unravel and solve for 'q' .  Let's do this !

p = (q+r)/12  + 4r

Subtract  (q+r)/12  from each side . . . p - (q+r)/12 = 4r

Subtract 'p' from each side . . . -(q+r)/12 = 4r - p

Multiply each side by -1 . . . (q+r)/12 = p - 4r

Multiply each side by 12 . . . (q+r) = 12p - 48r

Subtract 'r' from each side . . . <em>q = 12p - 49r</em>

5 0
4 years ago
What is the standard form of (2-4i)(3+5i) divided by (3+i)
jasenka [17]
First we need to simplify the numerator of the fraction

(2 - 4i)(3 + 5i)
= 6 +10i - 12i - 20i²
= 6 - 2i + 20
= 26 - 2i

So now the fraction becomes:

\frac{26-2i}{3+i}

In order to convert the fraction to standard form, we need to multiply and divide the fraction by the conjugate of the denominator as shown below:

\frac{26-2i}{3+i}* \frac{3-i}{3-i}   \\  \\ &#10;= \frac{78-26i-6i+2i^{2} }{9-i^{2} } \\  \\ &#10;= \frac{78-32i-2}{9+1} \\  \\ &#10;= \frac{76-32i}{10} \\  \\ &#10;= \frac{76}{10}- \frac{32i}{10} \\  \\ &#10;= \frac{38}{5}- \frac{16}{5}i
4 0
3 years ago
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