So you need the solve for x and y ?
from 8x-y = 10,
y = 8x -10
Plug this in other equation.
8x-10 = x^2 +12x + 30
Re-arrange and combine like terms,
x^2 +12x -8x +30+10 = 0
x^2 +4x +40 = 0
This does not have any real solutions.
So there are no real values of x and y satisfying the 2 equations.
Are you sure the question is correct? or if this question belongs to complex numbers topic?
Answer:
probability=events over the sample space
5x-3x^2/2x^4 =x(5-3x) / 2x.(x^3), simplified by x, we have <span>5-3x/2x^3, (x≠0)
</span>so the answer is <span>C.5-3x/2x^3, (x≠0)</span>
Answer:
1
Step-by-step explanation:
Answer:
Opposite sides are equal
Diagonals bisect each other
Step-by-step explanation:
