So we are given the mean and the s.d.. The mean is 100 and the sd is 15 and we are trying the select a random person who has an I.Q. of over 126. So our first step is to use our z-score equation:
z = x - mean/s.d.
where x is our I.Q. we are looking for
So we plug in our numbers and we get:
126-100/15 = 1.73333
Next we look at our z-score table for our P-value and I got 0.9582
Since we are looking for a person who has an I.Q. higher than 126, we do 1 - P. So we get
1 - 0.9582 = 0.0418
Since they are asking for the probability, we multiply our P-value by 100, and we get
0.0418 * 100 = 4.18%
And our answer is
4.18% that a randomly selected person has an I.Q. above 126
Hopes this helps!
Answer:
A i think
Step-by-step explanation:
A= player A runs batted in
b= player B runs batted in= a-13
250= a + b
substitute b= a-13 for b
250= a + (a-13)
combine like terms
250= 2a -13
add 13 to both sides
263= 2a
divide both sides by 2
131.5= a
Substitute a= 131.5 into equation
250= a + b
250= 131.5 + b
subtract 131.5 from both sides
118.5= b
Hope this helps! :)
They need to start the test no later than 10:10
10:10 + 1 1/2 hours = 11:40
Hope this helps
-AaronWiseIsBae
