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Viktor [21]
3 years ago
13

Solve for x. Give your answer in simplest radical form

Mathematics
1 answer:
Tasya [4]3 years ago
3 0
Use the Pythagorean Theorem to find the length of the side marked "x."
x^2 + (10 mi)^2 = (13 mi)^2.  Thus, x^2 + 100 mi^2 = 169 mi^2.
Next, x^2= (169-100) mi^2, or x^2 = 69 mi^2.  Find the positive square root of both sides of this equation.  What is it?
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Louisa needs 3 liters of lemonade and punch for a picnic she has 1800 milliliters of lemonade. How much punch does she need expl
8090 [49]
There are 1000 millimetres in a litre, so 1800 ml is 1.8 litres. 3-1.8 is 1.2.
5 0
3 years ago
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A line is defined by the equation y=2/3x-6. The line passes through a point whose y-coordinate is 0. What is the x-coordinate of
adelina 88 [10]
Y = (2/3).x - 6. If y=0, then 0= (2/3).x - 6. Solve for x:

2x/3 - 6 = 0
Same denominator:
(2x - 18)/3 = 0
2x - 18 = 0
2x = 18 and x = 9 (x-coordinate)
 

6 0
3 years ago
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What does x equal in this problem
Yakvenalex [24]

Answer:

89

Step-by-step explanation:

it equals 180-91

or 89

3 0
3 years ago
The radius of a circle is 3.9 in. Find the circumference to the nearest tenth.
masha68 [24]

Answer:

C = 24.5 in

Step-by-step explanation:

Formula to find the circumference of a circle is :

C = 2πr

Here,

r ⇒ radius

So let us solve now.

C = 2πr

C = 2 × π × r

C = 2 × 3.14 × 3.9

C = 24.492 in

So, they've asked for nearest 10th.

Therefore, the answer will be 24.5 in.

Hope this helps you :-)

Let me know if you have any other questions :-)

8 0
2 years ago
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The sector COB is cut from the circle with center O. The ratio of the area of the sector removed from the whole circle to the ar
mafiozo [28]

Answer:

Ratio = \frac{R^2 - r^2 }{ r^2}

Step-by-step explanation:

Given

See attachment for circles

Required

Ratio of the outer sector to inner sector

The area of a sector is:

Area = \frac{\theta}{360}\pi r^2

For the inner circle

r \to radius

The sector of the inner circle has the following area

A_1 = \frac{\theta}{360}\pi r^2

For the whole circle

R \to Radius

The sector of the outer sector has the following area

A_2 = \frac{\theta}{360}\pi (R^2 - r^2)

So, the ratio of the outer sector to the inner sector is:

Ratio = A_2 : A_1

Ratio = \frac{\theta}{360}\pi (R^2 - r^2) : \frac{\theta}{360}\pi r^2

Cancel out common factor

Ratio = R^2 - r^2 : r^2

Express as fraction

Ratio = \frac{R^2 - r^2 }{ r^2}

6 0
2 years ago
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