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Viktor [21]
3 years ago
13

Solve for x. Give your answer in simplest radical form

Mathematics
1 answer:
Tasya [4]3 years ago
3 0
Use the Pythagorean Theorem to find the length of the side marked "x."
x^2 + (10 mi)^2 = (13 mi)^2.  Thus, x^2 + 100 mi^2 = 169 mi^2.
Next, x^2= (169-100) mi^2, or x^2 = 69 mi^2.  Find the positive square root of both sides of this equation.  What is it?
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When n = 1, 2(1) + 1 = 3

When n = 2, 2(2) + 1 = 5

When n = 3, 2(3) + 1 = 7

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----------------------------------------------------
Answer: 35
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The remainder from the division of the algebraic equation is -53/8.

<h3>What is the remainder of the algebraic expression?</h3>

The remainder of the algebraic expression can be determined by using the long division method.

Given that:
\mathbf{f(x) = \dfrac{x^3 - 6x^2 + 3x - 1}{2x-3}}

where:

  • The divisor = 2x -3

Using the long division method, we have:

\mathbf{= \dfrac{x^2}{2} +\dfrac{-\dfrac{9x^2}{2}+3x -1 }{2x-3}}

\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} +\dfrac{-\dfrac{-15x}{4}-1 }{2x-3}}

\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} -\dfrac{15}{8}+\dfrac{-\dfrac{53}{8} }{2x-3}}

\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} -\dfrac{15}{8}-\dfrac{53 }{8(2x-3)}}

Therefore, we can conclude that the remainder is -53/8.

Learn more about the division of algebraic equations here:

brainly.com/question/4541471

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