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gogolik [260]
2 years ago
9

Can anyone tell me how you could describe this answer to the equation?

Mathematics
1 answer:
DanielleElmas [232]2 years ago
8 0

The end behavior of the given polynomial is that as x → -∞ or  x → ∞, then, f(x) → 5

<h3>What is the end behavior of the Polynomial?</h3>

We are given the polynomial;

f(x) = 5x/(x - 25)

Now, we want to find the limits as x → ±∞. Let us rearrange the given polynomial to get; f(x) = 5/(1 - (25/x))

Thus, applying limits we have;'

lim x → ±∞ [5/(1 - (25/x))]

From algebraic limit laws we know that;

If f(x) = k, then;

lim x → +∞ [f(x)] = k

Also, lim x → -∞ [f(x)] = k

Thus, applying limits at infinity to our polynomial gives;

lim x → ±∞ [5/(1 - (25/x))] = 5/(1 - 0) = 5

This is because lim x → ∞ for 1/x is 0.

Thus, f(x) has horizontal asymptotes at y = 5

Thus, we conclude that the end behavior is that as x → -∞ or  x → ∞, then, f(x) → 5

Read more about Polynomial End behavior at; brainly.com/question/20347699

#SPJ1

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<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%20%7Bw%7D%5E%7B6%7D%20%20%7Bv%7D%5E%7B5%7D%20%7D%7B15%20%7Bw%7D%5E%7B2%7D%20v%7
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Breaking down:
\frac{3}{15}  =  \frac{1}{5}
{w}^{6}  \div  {w}^{2}  =  {w}^{4}
{v}^{5}  \div v =  {v}^{4}

Therefore,
\frac{3 {w}^{6} {v}^{5} }{15 {w}^{2}v } \\  =  \frac{{w}^{4} {v}^{4}  }{5}

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