All categories

3 years ago

Solve for the variable: x + 9 > -4

Mathematics

2 answers:

cestrela7 [59]3 years ago

5 0

X+9>-4
-9 -9
x>-13 is the answer

Marina CMI [18]3 years ago

3 0

$Hi \\ \\ x+9\ \textgreater \ -4 \\ \\ x\ \textgreater \ -4-9 \\ \\ \boxed{x\ \textgreater \ -13} \\ \\ S=\{x\in~\mathbb{R} |x\ \textgreater \ -13\} \\ \\ \\$

You might be interested in

Capital Value Find the capital value of an asset that generates $7200 yearly income if the interest rate is as follows.

olganol [36]

a. An asset that generates $7200 yearly income if the interest rate 5% compounded continuously, then its capital value is $140433.002

b. An asset that generates $7200 yearly income if the interest rate 10% compounded continuously, then its capital value is $68460.59

Step-by-step explanation:

For continuously compound interest

$A = P \times e^{r t}$ ---------------> eq.1

Where

P = principal amount (initial investment)

r = annual interest rate (as a decimal)

t = number of years

A = amount after time t.

Let’s solve the equation

Where,

P is unknown

A = P + 7200 (asset after 1 year) ---------------> eq. 2

Case A:

$r=\frac{\text {interest rate}}{100}=\frac{5}{100}=0.05$

t = 1 (1 year)

Substitute all values in the formula (2) using the formula (1),

$P \times e^{(0.05)(1)}=P+7200$

$P \times e^{0.05}-P=7200$

$P\left(e^{0.05}-1\right)=7200$

$P(1.05127-1)=7200$

$P(0.05127)=7200$

$P=\frac{7200}{0.05127}=\$140433.002$

Case B:

$r=\frac{\text {interest rate}}{100}=\frac{10}{100}=0.10$

t = 1 (1 year)

Substitute all values in the formula (2) using the formula (1),

$P \times e^{(0.10)(1)}=P+7200$

$P \times e^{0.10}-P=7200$

$P\left(e^{0.10}-1\right)=7200$

$P(1.10517-1)=7200$

$P(0.10517)=7200$

$P=\frac{7200}{0.10517}=\$68460.59$

7 0

2 years ago

Can I plz have some help

ella [17]

I think it is 63 because a triangle equals 180

6 0

3 years ago

Musa ships cars into Ghana, Nigeria and Benij republic from the United States of America. The import duty costs are 10%, 25% and

babunello [35]

The Benz C300 markup should be $15525. The markup price for the new Toyota Highland should be $43470

Step-by-step explanation:

For the used Benz C300

Initial price $12,000

Apply import duty for Nigeria which is 25%, which is similar to increasing the price by 25%

100% +25%=125%

12000*125/100 = $15000

Apply the 15% profit

100%+15%=115%

15000*115/100 =$17250

Apply the 10% discount, reducing the price by 10%

100%-10%=90%

17250*90/100 =$15525

The Benz C300 markup should be $15525

For the Toyota Highlander

Initial price = $30,000

Apply import duty for Nigeria for new cars, which is 40%, which is similar to increasing the car price by 40%

100%+40%=140%

30,000*140/100 =$42000

Apply the 15% profit

15%+100%=115%

115/100*42000 =$48300

Apply the 10% discount

100%-10%=90%

48300*90/100=$43470

The markup price for the new Toyota Highland should be $43470

Learn More

Percentage increase and decrease :brainly.com/question/11537235

Keywords : cars, import duty, cost, minimum profit, discount, reseller

#LearnwithBrainly

6 0

2 years ago

A grocery store’s receipts show that Sunday customer purchases have a skewed distribution with a mean of 27$ and a standard devi

34kurt

Answer:

(a) The probability that the store’s revenues were at least $9,000 is 0.0233.

(b) The revenue of the store on the worst 1% of such days is $7,631.57.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sum of values of X, i.e ∑X, will be approximately normally distributed.

Then, the mean of the distribution of the sum of values of X is given by,

$\mu_{X}=n\mu$

And the standard deviation of the distribution of the sum of values of X is given by,

$\sigma_{X}=\sqrt{n}\sigma$

It is provided that:

$\mu=\$27\\\sigma=\$18\\n=310$

As the sample size is quite large, i.e. n = 310 > 30, the central limit theorem can be applied to approximate the sampling distribution of the store’s revenues for Sundays by a normal distribution.

(a)

Compute the probability that the store’s revenues were at least $9,000 as follows:

$P(S\geq 9000)=P(\frac{S-\mu_{X}}{\sigma_{X}}\geq \frac{9000-(27\times310)}{\sqrt{310}\times 18})\\\\=P(Z\geq 1.99)\\\\=1-P(Z$