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MariettaO [177]
4 years ago
5

If you can answer any of these please do and put the question number by the answer

Mathematics
1 answer:
ch4aika [34]4 years ago
7 0

Answer:

33. D.1/3

34. D. y= x+4

35. Slope= -2/3 Y-intercept= -6

Step-by-step explanation:

For number 33. D. 1/3 is the correct answer.

<em>Start at the point (0,2) Then, Go up 1 and Right 3. </em>

<em>As a result, you land in the point (3,3) This proves that the slope is 1/3.</em>

Note: the line is increasing and going upwards, so the slope is positive.

For number 34. D. y=x+4 is the correct answer.

<em>When writing an equation of a line, the correct format is y=mx+b. We are given both m and b. So all we have to do is plug these values into the equation y=mx+b. As a result, we get y=1x+4, which also means y=x+4</em>

For number 35. The Correct answer is: Slope= -2/3 Y-intercept= -6

<em>For this question I can't see all the answer choices but I know that the  Slope is -2/3  and the Y-intercept is -6. Here's why: First you need to transform the equation 2x+3y=-18 into y=mx+b format. To do this, subtract -2x from both sides of the equation and you are left with 3y=-18-2x. You can flip -18 and -2x which makes the equation 3y=-2x-18. The next step is to divide both sides of the equation by 3, which gives you y=-2/3x-6. This means </em>Slope= -2/3 and Y-intercept= -6

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Answer:

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Step-by-step explanation:

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The value of cot λ is:

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3 years ago
In ΔCDE, the measure of ∠E=90°, DE = 39 feet, and CD = 89 feet. Find the measure of ∠C to the nearest degree.
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Sever21 [200]

Answer:

Okay, I think you mean't 4x-9=6x+12.

Step-by-step explanation:

x=-7

6 0
4 years ago
Help please solve<br> <img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B6x%5E5%2B11x%5E4-11x-6%7D%7B%282x%5E2-3x%2B1
Shkiper50 [21]

Answer:

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They relate one or more variables with comparison operators other than the equality.

We must find the set of values for x that make the expression stand

\displaystyle \frac{6x^5+11x^4-11x-6}{(2x^2-3x+1)^2} \leq 0

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\displaystyle \frac{(x-1)(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)^2(x-\frac{1}{2})^2} \leq 0

Simplifying by x-1 and taking x=1 out of the possible solutions:

\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0

We need to find the values of x that make the expression less or equal to 0, i.e. negative or zero. The expressions

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The first inequality gives us the solution

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The second inequality gives no solution because it's impossible to comply with both conditions.

Thus, the solution for the given inequality is

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3 years ago
How do you solve the quadratic equation (x-2)^=49
Usimov [2.4K]
Assuming you mean
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x-2=+/-7
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7 0
3 years ago
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