Convert the mixed number <span>21 <span>2/3</span></span><span> into an </span><span>improper fraction.
</span>15⋅<span>65/3
</span><span>Cancel 3 and 15.
</span><span>5⋅65
</span>Multiply 5<span> by </span>65<span> to get </span><span>325.
</span>325
Answer:
325
<h3>(-3j²k³)²(2j²k)³</h3>
(-3j²k³)²(2j²k)³ = <em>When a power is raised to a power the exponents have to be multiplied.</em>
= (-3²j⁽²*²⁾k⁽³*²⁾)(2³j⁽²*³⁾k³) = <em>We can take out the constants</em>
= (9)(8)(j⁴k⁶)(j⁶k³) = <em>We can group the same variables</em>
= 72(j⁴j⁶)(k⁶k³) = <em>When multiplying two powers that have the same base, you have to add the exponents.</em>
= 72 j⁽⁴⁺⁶⁾k⁽⁶⁺³⁾ = 72j¹⁰k⁹
Answer = 72j¹⁰k⁹
Hope this helps!
Answer: The first number that appears in both sequences is 28.
Step-by-step explanation:
Let's write down numbers from each of the sequences
Sequence 1) We need to start from 7 and multiply 4
7x4=28, 28x4=112
The sequence is 7,28,112...
Sequence 2) We need to start from 8 and add 5
5+8=13, 13+5=18, 18+5=23, 23+5=28
The sequence is 8,13,18,23,28...
They both have 28
No it is not because its more then ten numbers away from the solution of the five tickets