Y-intercept = -13
x-intercept = 2.6 or 2 3/5
-13 is the y-intercept. In the equation, y=mx+b, b is the y-intercept. Looking at the equation, y=5x-13, we can see that -13 is in the place of b, therefore -13 is the y-intercept.
() is the x-intercept. To find the x-intercept, you need to replace values into the equation. Since the coordinates for the x-intercept consist of y being 0, you must replace y in the equation. with 0.
0=5x-13
Get rid of the -13 by adding it onto both sides. -13 is negative and the opposite of a negative is positive, thus making you add to get rid of -13.
0=5x-13
+13 +13
13=5x
Now you divide 5 from both sides to get rid of 5. The opposite of multiplication is division, so you must divide the 5 from 5x to isolate the x.
13/5=5x/5
2.6 or 2 3/5=x
Therefore the coordinates (2.6,0) represent the x-intercept, or just 2.6.
I hope this helped.
The answer here is c. You get this by following the path of 3 to the right and up 8
The goal here is to find the cost of the painting BEFORE the 60% increase.
To find the cost of the painting, we must take in the information we already have:
Increase percent: 60%
Original price: unknown
Price after increase: $400
$400 is the price of the painting AFTER the increase has been added. So this equals the cost of the painting before the increase, plus the total amount of the increase (which is 60% of the original price).
The total must be (100% + 60% = 160%) 160% of the original painting price.
To find the original price, we must divide the increased price by the new percentage (160%). But how do we get here?
Well, we have 160% and our (fraction) $400/1%. We will have to switch the 160% and the 1%, giving us..
1% $400/160%
We take 400/160, which is 2.5. But this is only 1% of the original price! We want 100%.
So now, we multiply the 2.5 by 100 to get our answer: $250.
I hope this helps! If you have any questions, feel free to ask.
Both dimensions were increased by 127.
The other response seems more complex so probably ignore mine. I probably misinterpreted the question.
