Ask question

Ask question

All categories

3 years ago

11

Question 1

1 answer:

AVprozaik [17]3 years ago

5 0

Answer: Chowder

Step-by-step explanation: Chowder is the answer for this question because the equation form of chowder will explain. If you do not understand the Chowder Equation Theorem, simply search it up and you will be provided with knowledge of what to do. (x, y + 6)

It’s 3,11

You might be interested in

The total surface area of a cube is 294 cm ² work out the volume of the cube

mihalych1998 [28]

$\text{ Total Surface Area of cube, with Side $a$ is } 6a^2 \\ \text{ (six times the area of each face)} \\ 6a^2=294 \ m^2 \\ a^2= \frac{294}{6} \\ a^2=\frac{49\times6}{6} \\ a^2=49 \\ a=\sqrt{49} \\ a=7 \ m \\ \text{Volume of cube with Side $a$ is } a^3 \\ V= 7^3=49\times7 \\ \text{volume of the cube is } 343 \ m^3$

6 0

3 years ago

Read 2 more answers

PLEASE PLEASE HELP ME I DONT UNDERSTAND THIS SUBJECT PLESASE!!!!!!!!!!!!!!

lana [24]

Answer:

3

Step-by-step explanation:

6 0

3 years ago

Fill in the blank.<br> (5x)2<br> a0x2

Yuki888 [10]

Answer: $a_0=25$

Step-by-step explanation:

It is given that, $(5x)^2=a_0x^2$

We need to find the value of $a_0$

As $(5x)^2=a_0x^2$

Solving LHS

$25x^2=a_0x^2$

Now comparing the coefficients of $x^2$

In LHS the coefficient of $x^2$ is 25

In RHS the coefficient of $x^2$ is $a_0$

It implies that, $a_0=25$

So, the value of $a_0$ is 25.

5 0

3 years ago

Convert y+7=4(x-3) standard form

True [87]

Answer:

-4x+y = -5

Step-by-step explanation:

Y+7=4(x-3)

Y+7=4x-12

+7. +7

Y=4x-5

-4x+y=-5

7 0

3 years ago

Please answer with clear instructions so that i can apply this to other questions

marishachu [46]

Answer:

1 and - 1

Step-by-step explanation:

The equation of a line passing through the origin is

y = mx ( m is the slope ( gradient ) )

y = x ← is in this form

with gradient m = 1

Parallel lines have equal gradients

Then the gradients of lines parallel to the given line is 1

Given a line with gradient m then the gradient of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{1}$ = - 1

Then the gradients of lines perpendicular to this line is - 1

4 0

2 years ago