All categories

3 years ago

What is the slope of a line parallel to the line whose equation is 3x – 4y = 8

1 answer:

7 0

Hi there! The answer is C.

We can find the slope of this line by making y the subject of the equation.

$3x - 4y = 8 \\ - 4y = - 3x + 8 \\ y = \frac{ - 3}{ - 4} x + \frac{8}{ - 4} \\ y = \frac{3}{4} x - 2$

Now we can see that the slope of this line (which is positioned in front of x) is 3/4. Therefore, the slope of any line parallel to this one is 3/4 as well. The answer is C.

You might be interested in

Simplify (12a^2b^6)^2

marishachu [46]

You go through and square each term in the parentheses
(12a^2b^6)^2 = (12)^2(a^2)^2(b^6)^2 =
144a^4b^12

6 0

3 years ago

Read 2 more answers

If g(x) = 5x2^2 - 10x + 9 and h(x) = -3x3^3+ 5x - 6, find g(x) - h(x)?

AnnZ [28]

Answer:

B) $g(x) - h(x) = 3x^3 - 5x^2 - 15x + 15$

Step-by-step explanation:

Here, the given functions are:

$g(x) = 5x^2- 10x + 9 \\h(x) = -3x^3+ 5x - 6$

Now, g(x) - h(x) is :

$(5x^2- 10x + 9) - ( -3x^3+ 5x - 6)\\= 5x^2- 10x + 9 + 3x^3 - 5x + 6\\= 3x ^3 + 5x ^2+ (-10 x - 5 x) + (9 + 6)\\= 3x^3 - 5x^2 - 15x + 15$

⇒ $(5x^2- 10x + 9) - ( -3x^3+ 5x - 6) = 3x^3 - 5x^2 - 15x + 15$

B) Hence, $g(x) - h(x) = 3x^3 - 5x^2 - 15x + 15$

3 0

3 years ago

Expand the expression and combine like terms:<br> 20(−1.5r+0.75)

PtichkaEL [24]

20( -1.5r + 0.75)
Multiply everything by 20

= -30r + 15

4 0

3 years ago

Read 2 more answers

498,147,846,267<br>+ 32,870,714,538<br>

san4es73 [151]

Answer:

531018560805

Step-by-step explanation:

4 0

3 years ago

Solve.

Nikitich [7]

The answer is C: $10\text{ }^1/_2$ . Here are the details:

$\text{Equation:}\\ 6\text{ }^1/_3+10\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 6+10=16\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^1/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^2/_6+\text{ }^3/_6=\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add 'em up!}\\
16\text{ }^5/_6$

$\text{Equation:}\\
16\text{ }^5/_6+3\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Start with the integers.}\\
16+3=19\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{...then with the fractions, but rewrite them first to make it easier.}\\
^5/_6+\text{ }^5/_6=\text{ }^{10}/_6\stackrel{\text{rewrite}}{\to}\text{ }^5/_3\stackrel{\text{rewrite}}{\to}1\text{ }^2/_3\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add 'em up!}\\
20\text{ }^2/_3$

$\text{Last equation:}\\ 20\text{ }^2/_3+5\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 20+5=25\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^2/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^4/_6+\text{ }^3/_6=\text{ }^7/_6\stackrel{\text{rewrite}}{\to}1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add the integer and fraction together.}\\
25+1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6$

$26\text{ }^1/_6\stackrel{\checkmark}{=}26\text{ }^1/_6$

5 0

3 years ago