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3 years ago

10

jen makes necklaces by stringing different color beads. each necklace is 18 inches long. jen has an 86-inch length of beaded str

ing. how many necklaces can she make?

2 answers:

miv72 [106K]3 years ago

4 0

You have to divide 86 by 18 .which she can make about 5 necklaces

Vedmedyk [2.9K]3 years ago

3 0

Its actually A-4 because 86 ÷18 is 4

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Triangle DEF is an isosceles, so DEF = DFE.

Katarina [22]

Answer:

m∠CFD= $105\°$

Step-by-step explanation:

we know that

m∠CFD+m∠DFE= $180\°$ ------> by supplementary angles

we have

that

m∠DFE=m∠DEF= $75\°$

so

m∠CFD+ $75\°=180\°$

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3 years ago

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Kashif bought a bicycle for rs 10000 and sold it for rs 8000 his loss percentage is

aleksley [76]

Answer:

20%

Step-by-step explanation:

Loss=C.P-S.P
Loss=10000-8000
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2 years ago

Write an equation in slope-intercept form for the line that passes through (1, 1), and is perpendicular to the graph of 3x + 2y

defon

Answer:

2X-3Y = -1

Step-by-step explanation:

given equation is 3X +2Y = -7

FIRST BRING THIS IN SLOPE INTERCEPT FORM

2Y = -3X -7

DIVIDING EACH TERM BY 2

Y = (-3/2)X -7/2

SLOPE OF GIVEN EQUATION IS -3/2

SLOPE OF LINE PERPENDICULAR TO THIS IS NEGATIVE RECIPROCAL HENCE SLOPE OF REQUIRED EQUATION IS 2/3

EQUATION OF STRAIGHT LINE IN POINT SLOPE FORM IS

Y-Y1 = m(X-X1)

Y-1 = (2/3)(X-1)

MULTIPLYING ALL TERMS BY 3

3(Y-1) = 2(X-1)

3Y-3 = 2X -2

2X-2 = 3Y-3

2X-3Y =-3+2

2X-3Y = -1

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3 years ago

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A farmer has 3/4 acre of land. He will use all the land and plant different vegetables in 1/16 -acre sections. How many sections

kati45 [8]

Answer: 12 sections of 1/16 acre

Step-by-step explanation:

We want to find how many sections of 1/16 acre we can have in a total area of 3/4 acre.

This is equal to the quotient between 3/4 and 1/16

Remember that if we have two rational numbers (a/b) and (c/d) the quotient can be writen as:

(a/b)/(c/d) = (a/b)*(d/c) = (a*d)/(b*c)

The quotient we want to solve is:

(3/4)/(1/16) = (3/4)*(16/1) = (3*16)/4 = 12

Then you can have 12 sections of 1/16 acre

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3 years ago

What is quartile 1 (Q1)quartile 3 (Q3) and the IQR? Answer all three parts . 13, 23, 24, 25, 26, 26, 37, 47, 47, 48, 50

Fittoniya [83]

Answer:

Quartile 1 (Q1) = 24

Quartile 2 (Q2) = 47

IQR = 23

Step-by-step explanation:

Given:

The set of data are:

13, 23, 24, 25, 26, <u>26</u>, 37, 47, 47, 48, 50

The data are in increasing order. The number terms are, $n = 11$ .

Therefore, the middle term = $\frac{n+1}{2}=\frac{11+1}{2}=6^{th}\ term$

So, the median = 26

Now, the median divides the set of data into two parts. The median of first part is the quartile 1 and the median of second part is quartile 2.

So, the first part has the following terms:

13, 23, <u>24</u>, 25, 26

Here also, $n=5$ . So, the third term is the median.

∴ Q1 = 24

The second part has the following terms:

37, 47, <u>47</u>, 48, 50

Here also, $n=5$ . So, the third term is the median.

∴ Q2 = 47.

Now, IQR = Q2 - Q1 = 47 - 24 = 23.

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3 years ago