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3 years ago

Is 0.1292387523 a rational number

Mathematics

1 answer:

evablogger [386]3 years ago

5 0

Yes bc it can be written as a fraction.

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The length of a rectangular computer chip is 22 x 10 cm and the width is 7 x 104 cm. Explain how to

mash [69]

Answer:

area = 160160 inches²

area = 1.6016 × 10⁵ inches²

Step-by-step explanation:

The length of the rectangular computer chip is 22 × 10 cm and the width is 7 × 104 cm .

The area of the rectangular computer chip is the product of the length and the width.

area = length × width

area = (22 × 10) × (7 × 104)

area = 220 × 728

area = 160160 inches²

In scientific notation

area = 1.6016 × 10⁵ inches²

160160 is written as 1.6016 × 10⁵ because 1.60160 × 100000 = 1.6016 × 10⁵

7 0

3 years ago

5x squared plus 4x plus 40

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No solution . This problem makes no sense .

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3 years ago

PLEASE HELP ME ANSWER THIS QUESTION 20 POINTS!!!

Sergeu [11.5K]

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4 years ago

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5(x+9) in the distributive property

Dominik [7]

5x + 45
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3 years ago

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From a bowl containing five red, three white, and seven blue chips, select four at random and without replacement. Compute the c

snow_lady [41]

Answer:

The probability is $\frac{5}{9}$

Step-by-step explanation:

Let A be the event of one red, zero white, and three blue chips,

And, B is the event of at least three blue chips,

Since, A ∩ B = A (because If A happens that it is obvious that B will happen )

Thus, the conditional probability of A if B is given,

$P(\frac{A}{B})=\frac{P(A\cap B)}{P(B)}=\frac{P(A)}{P(B)}$

Now, red chips = 5,

White chips = 3,

Blue chips = 7,

Total chips = 5 + 3 + 7 = 15

Since, the probability of one red, zero white, and three blue chips, when four chips are chosen,

$P(A)=\frac{^5C_1\times ^3C_0\times ^7C_3}{^{15}C_4}$

$=\frac{5\times 35}{1365}$

$=\frac{175}{1365}$

$=\frac{5}{39}$

While, the probability that of at least three blue chips,

$P(B)=\frac{^8C_1\times ^7C_3+^8C_0\times ^7C_4}{^{15}C_4}$

$=\frac{8\times 35+35}{1365}$

$=\frac{315}{1365}$

$=\frac{3}{13}$

Hence, the required conditional probability would be,

$P(\frac{A}{B})=\frac{5/39}{3/13}$

$=\frac{65}{117}$

$=\frac{5}{9}$

4 0

3 years ago