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marissa [1.9K]
3 years ago
5

rectangle with a perimeter of 1110 meters, this rectangular shape is 30 meters longer than 6 times its width. find its dimension

s
Mathematics
1 answer:
Alecsey [184]3 years ago
6 0

Answer:

The width of the rectangle is  75 meters and length is 480 meters.

Step-by-step explanation:

The perimeter of the rectangle = 1110 meters

Let the width of the rectangle = k meters

So,the length of the rectangle = 6k + 30

Now, PERIMETER OF A RECTANGLE = 2(LENGTH + WIDTH)

⇒ 1110 = 2( k + (6k + 30))

or, 1110 = 14 k + 60

or, 14 k = 1110 - 60 = 1050

⇒ k = 1050/14 = 75

Hence, the width of the rectangle is k =  75 meters

and the Length of the rectangle is 6k + 30 = 6(75) +30

= 480 meters

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A=bh

Now, if we consider the 9.9 inches side as the base, then the height is the one labeled with 5.5 inches.

If instead we choose the 11 inches side as the base, the height is h.

So, we can express the area in this two equivalent ways:

A = 9.9\cdot 5.5 = 11\cdot h

Solving for h, we have

h = \dfrac{9.9\cdot 5.5}{11} = 4.95

8 0
3 years ago
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mr Goodwill [35]

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3 years ago
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Answer:

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Step-by-step explanation:

Given that:

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Multiplying both sides by 3/2

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Answer:

Step-by-step explanation:

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