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sineoko [7]
3 years ago
15

Solve all values of X by factoring:

title="x^{2} +6x+4=-2+4" alt="x^{2} +6x+4=-2+4" align="absmiddle" class="latex-formula">

Mathematics
2 answers:
Misha Larkins [42]3 years ago
8 0

Answer:

Factoring not possible

x = -3 + sqrt(7), -3 - sqrt(7)

Or,

x = 0, -8

Step-by-step explanation:

x² + 6x + 4 = 2

x² + 6x + 2 = 0

Doesn't have rational roots

Quadratic formula:

By - 4AC = 6² - 4(1)(2) = 28

Sqrt(28) = 2sqrt(7)

x = [-6 +- 2sqrt(7)]/2

x = -3 +- sqrt(7)

x = -3 + sqrt(7), -3 - sqrt(7)

If the equation is:

x² + 6x + 4 = -2x + 4

x² + 8x = 0

x(x + 8) = 0

x = 0, -8

bulgar [2K]3 years ago
3 0

⚡⚡⚡⚡⚡⚡⚡⚡⚡⚡⚡⚡⚡⚡⚡⚡⚡

<em><u>hope it helps you see the attachment for further information...... </u></em>

<em><u>✨</u></em><em><u>✨</u></em><em><u>✨</u></em><em><u>✨</u></em><em><u>✨</u></em><em><u>✨</u></em><em><u>✨</u></em><em><u>✨</u></em><em><u>✨</u></em><em><u>✨</u></em><em><u>✨</u></em><em><u>✨</u></em><em><u>✨</u></em><em><u>✨</u></em><em><u>✨</u></em><em><u>✨</u></em><em><u>✨</u></em>

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3 years ago
Y=x² + 16x + 64
motikmotik

I'll do the first one to get you started

The equation y = x^2+16x+64 is the same as y = 1x^2+16x+64

Compare that to y = ax^2+bx+c and we see that

a = 1

b = 16

c = 64

Use the values of 'a' and b to get the value of h as shown below

h = -b/(2a)

h = -16/(2*1)

h = -8

This is the x coordinate of the vertex.

Plug this x value into the original equation to find the corresponding y value of the vertex.

y = x^2+16x+64

y = (-8)^2 + 16(-8) + 64

y = 0

Since the y coordinate of the vertex is 0, this means k = 0.

The vertex is (h,k) = (-8, 0)

---------------------

So we found that a = 1, h = -8 and k = 0

Therefore,

f(x) = a(x-h)^2 + k

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is the vertex form

---------------------

<h3>Final answer to problem 1 is f(x) = (x+8)^2 </h3>
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3 years ago
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