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Leviafan [203]
3 years ago
13

If angle LNM =8x+12 and angle JNL =12x-32, find the measure of angle JNP.(JNP and LNM are congruent.

Mathematics
1 answer:
sasho [114]3 years ago
3 0
Sum\ of\ congrugent\ angles\ is\ 180^{\circ}.\\\\
LNM+JNL=180^{\circ}\\\\
8x+12+12x-32=180\\\\
20x-20=180 \ \ \ |Add\ 20\\\\
20x=200\ \ \ |Divide\ by\ 20\\\\
x=10\\\\
JNL=12x-32=12*10-32=120-32=88^{\circ}
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A fisherman traveled in a boat from point N upstream. After having traveled 6 km, he stopped rowing and 2 hour 40 min after firs
Nat2105 [25]

Answer:

The speed of the river's current is 4.5 km/hr.

Step-by-step explanation:

Given : A fisherman traveled in a boat from point N upstream.

After having traveled 6 km, he stopped rowing and 2 hour 40 min after first leaving N, he was brought back to N by the current.

Knowing that the speed of the boat in still water is 9 km/hour

To find : The speed of the river’s current.

Solution :

Let the speed of current  = x km/h

Speed of boat = 9 km/h

Thus, the speed in upstream = (9 - x) km/h

Also, the speed in downstream = x km/h (because the boat is stationary in downstream)

Total distance = 6 km ( from N to the point he reached )

Total time = 2 hours 40 minutes

\text{2 hours 40 minutes}=2\frac{40}{60}=2 \frac{2}{3} \\\\\text{2 hours 40 minutes}=\frac{8}{3} \text{ hours}

We know, \text{Time} = \frac{\text{Distance}}{\text{Speed}}

According to the question,

\frac{6}{9-x}+\frac{6}{x}=\frac{8}{3}

Taking LCM and 6 common

6[\frac{x+9-x}{(9-x)x}]=\frac{8}{3}

Take 6 to another side,

\frac{9}{9x-x^2}=\frac{8}{3\times 6}

Cross multiply,

9\times 18=8\times(9x-x^2)

162=72x-8x^2

Taking 4 common and cancel out

4x^2-36x+81=0

Solve quadratic equation by middle term split,

4x^2-18x-18x+81=0

2x(2x-9)-9(2x-9)=0

(2x-9)(2x-9)=0

\Rightarrow 2x-9=0

\Rightarrow x=\frac{9}{2}=4.5

Therefore, The speed of the river's current is 4.5 km/hr.

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3 years ago
When a certain polynomial is divide by binomial x-3, the result is 4x-5+6/x-3. What is the polynomial
Dmitry_Shevchenko [17]
\frac{p(x)}{x-3} = 4x-5 + \frac{6}{x-3}

The polynomial p(x) can be found by multiplying 'x-3' to every term
p(x) = (4x-5)(x-3) + 6

Now distribute and you have your answer.
p(x) = 4x^2 -12x-5x+15 +6 \\  \\ p(x) = 4x^2 -17x+21


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You are given the parametric equations x=2cos(θ),y=sin(2θ). (a) List all of the points (x,y) where the tangent line is horizonta
vladimir1956 [14]

Answer:

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m = -\frac{\cos 2\theta}{\sin \theta}

The tangent line is horizontal when m = 0. Then:

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\theta = \frac{1}{2}\cdot \cos^{-1} 0

\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right), for all i \in \mathbb{N}_{O}

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The first four solutions are:

x:   \sqrt{2}   -\sqrt{2}  -\sqrt{2}  \sqrt{2}

y:     1        -1        1     -1

The solutions listed from the smallest to the greatest are:

x:  -\sqrt{2}   -\sqrt{2}  \sqrt{2}  \sqrt{2}

y:      -1         1     -1     1

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