Answer: the tuition in 2020 is $502300
Step-by-step explanation:
The annual tuition at a specific college was $20,500 in 2000, and $45,4120 in 2018. Let us assume that the rate of increase is linear. Therefore, the fees in increasing in an arithmetic progression.
The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = $20500
The fee in 2018 is the 19th term of the sequence. Therefore,
T19 = $45,4120
n = 19
Therefore,
454120 = 20500 + (19 - 1) d
454120 - 20500 = 19d
18d = 433620
d = 24090
Therefore, an
equation that can be used to find the tuition y for x years after 2000 is
y = 20500 + 24090(x - 1)
Therefore, at 2020,
n = 21
y = 20500 + 24090(21 - 1)
y = 20500 + 481800
y = $502300
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Answer:
3n−32=7n+28
n=-15
Step-by-step explanation:
Let's solve your equation step-by-step.
3n−32=7n+28
Step 1: Subtract 7n from both sides.
3n−32−7n=7n+28−7n
−4n−32=28
Step 2: Add 32 to both sides.
−4n−32+32=28+32
−4n=60
Step 3: Divide both sides by -4.
−4n/−4=60/−4
n=−15
The formula that you will use will be the formula for the area of a circle, which is as follows:
A= Pi r^2
(Pi times the radius squared)
The rule is that after the first term, every term after that is made out of
the smallest power of 2 that hasn't been used yet, with a zero after it.
