The only way i can think of doing that is by rounding and then subtracting....so
976 is closer to 1000, 522 is closer to 500 so 1000-500=500
I think Your answer is 500.
The answer is B. Hope that helped.
The length of the KN is 4.4
Step-by-step explanation:
We know from Pythagoras theorem
In a right angle ΔLMN
Base² + perpendicular² = hypotenuse
²
From the properties of triangle we also know that altitudes are ⊥ on the sides they fall.
Hence ∠LKM = ∠NKM = 90
°
Given values-
LM=12
LK=10
Let KN be “s”
⇒LN= LK + KN
⇒LN= 10+x eq 1
Coming to the Δ LKM
⇒LK²+MK²= LM²
⇒MK²= 12²-10²
⇒MK²= 44 eq 2
Now in Δ MKN
⇒MK²+ KN²= MN²
⇒44+s²= MN² eq 3
In Δ LMN
⇒LM²+MN²= LN²
Using the values of MN² and LN² from the previous equations
⇒12² + 44+s²= (10+s)
²
⇒144+44+s²= 100+s²+20s
⇒188+s²= 100+s²+20s cancelling the common term “s²”
⇒20s= 188-100
∴ s= 4.4
Hence the value of KN is 4.4
3y^-4 × (2y^-4) = 6y^-8
= 6/1/y^8
= 6/y^8
.................................................
1) When x^1 multiply with x^2, 1 will add to 2 and become 3
= x^3
2) y^-1 = 1/y
3^-2 = 1/3^2 = 1/9
5^-2 = 1/5^2 = 1/25
Take the log (base 4) of both sides of the equation.
![\log_{4}(\frac{1}{\sqrt{8}}) = m + 2](https://tex.z-dn.net/?f=%5Clog_%7B4%7D%28%5Cfrac%7B1%7D%7B%5Csqrt%7B8%7D%7D%29%20%3D%20m%20%2B%202)
![\frac{-1}{2} \log_{4}(4^{\frac{3}{2}})-2 = m](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B2%7D%20%5Clog_%7B4%7D%284%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%29-2%20%3D%20m)
![-2 \frac{3}{4}= m](https://tex.z-dn.net/?f=-2%20%5Cfrac%7B3%7D%7B4%7D%3D%20m)
The appropriate choice is ...
m = -11/4