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3 years ago

If f(x)=x*−81 and g(x)=(x−9)−1(x+9), find g(x)×f(x).

1 answer:

7 0

F(x) = x²-81

g(x) = (x-9) -1(x+9)

= (x-9) -x-9

g(x) • f(x)

= [x²-81 ] • [ (x-9) -x-9 ]

=[ x²-81 ] • [ (x-x -9-9) ]
= [ x²-81 ] •[0-18]
= [ x²-81] •[ -18]

= -18•x² +-81•-18
= -18x²+1458

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The sum of two numbers is equal to 11 and the difference is 19. What are the two numbers?

charle [14.2K]

$\bold{\huge{\pink{\underline{ Solution }}}}$

We have given in the question that, 

The sum of 2 numbers is equal to 11
The difference between two numbers is 19 .

$\bold{\underline{ To \: Find }}$

We have to find the value of x and y.

$\bold{\underline{ Let's \: Begin }}$

Let the two numbers be x and y

According to the question, 

$\sf{ x + y = 11......eq(1) }$

$\sf{ x - y = 19......eq(2) }$

Solving eq( 1 ) we get :- 

$\sf{ x + y = 11 }$

$\sf{ x = 11 - y ......eq(3 ) }$

Subsituting eq(3 ) in eq(2) :-

$\sf{ x - y = 19 }$

$\sf{ ( 11 - y) - y = 19 }$

$\sf{ 11 - y - y = 19 }$

$\sf{ 11 - 2y = 19 }$

$\sf{ - 2y = 19 - 11 }$

$\sf{ - 2y = 8}$

$\sf{ y = 8/(-2) }$

$\sf{ y = - 4 }$

$\sf{\red{Thus ,\: the\: value\: of \: y = -4}}$

Now, Subsitute the value of y in eq( 3 ) :-

$\sf{ x = 11 - y }$

$\sf{ x = 11 - (-4 ) }$

$\sf{ x = 11 + 4 }$

$\sf{ x = 15 }$

Hence, The value of x and y are 15 and (-4) .

5 0

3 years ago

HELP ME AND I WILL GIVE BRAINLIST AND 15 POINTS

Yakvenalex [24]

Answer:

im not 100% sure but i think the first one is 544, the second is 549 and the last is 551

545 goes in the second one

Step-by-step explanation:

mark brainliest if you want <3

7 0

3 years ago

Read 2 more answers

Suppose the weights of farmer carl's potatoes are normally distributed with a mean of 8.0 ounces and a standard deviation of 1.1

denis23 [38]

Given that the weights of farmer carl's potatoes are normally distributed with a mean of 8.0 ounces and a standard deviation of 1.1 ounces.

The probability of a normally distributed data between two values (a, b) is given by:

$P(a\ \textless \ X\ \textless \ b)=P\left(z\ \textless \ \frac{b-\mu}{\sigma/\sqrt{n}} \right)-P\left(z\ \textless \ \frac{a-\mu}{\sigma/\sqrt{n}} \right) \\ \\ =P(7.5\ \textless \ X\ \textless \ 8.5)=P\left(z\ \textless \ \frac{8.5-8.0}{1.1/\sqrt{6}} \right)-P\left(z\ \textless \ \frac{7.5-8.0}{1.1/\sqrt{6}} \right) \\ \\ =P(z\ \textless \ 1.113)-P(-1.113)=0.8672-0.1328=0.7344$