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Charra [1.4K]
3 years ago
8

Give the products of the reaction of butanal, with: (a) sodium borohydride, in methanol (b) hydrogen cyanide, with catalytic cya

nide (c) potassium dichromate in dilute sulfuric acid; (d) methanol, with a trace of acid catalyst; (e) ethylamine (CH3CH2NH2)

Chemistry
1 answer:
miss Akunina [59]3 years ago
4 0

Answer:

Answers are given below

Explanation:

(a) Aldehyde groups are reduced by sodium borohydride in methanol to give alcohol.

So, butanal produces butanol on reaction with sodium borohydride in methanol.

(b) Aldehyde forms cyanohydrin when they are treated with HCN with catalytic cyanide.

(c) Aldehydes are oxidized by potassium dichromate in dil. sulphuric acid to produce carboxylic acid.

(d) Aldehyde produces acetal with methanol and a trace amount of acid catalyst.

(e) Aldehyde gives condensation reaction with CH_{3}CH_{2}NH_{2} to produce imine.

Structures of products for the given reaction has been shown below.

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A water bottle has a mass of 14.0g. Given a density of 1.38g/cm^3, what is the volume of the plastic used to make the water bott
Kipish [7]

Answer:

\boxed{\sf Volume \ of \ plastic \ used = 10.14 \ cm^3}

Given:

Mass = 14.0 g

Density (\rho) = 1.38 g/cm³

To Find:

Volume (V)of the plastic used to make water bottle

Explanation:

Formula:

\boxed{ \bold{Density \ (\rho) = \frac{Mass \ (m)}{Volume \ (V)}}}

Substituting value of m & density in the formula:

\sf \implies 1.38 =  \frac{14.0}{V} \\  \\   \sf \implies V =  \frac{14.0}{1.38} \\  \\   \sf \implies V = 10.14 \ cm^3

\therefore

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3 years ago
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Answer: heat

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The compound ncl3 is nitrogen trichloride, but alcl3 is simply aluminum chloride. why
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The answer to this question would be:
NCl3 is a molecular compound (two or more nonmetals), and therefore in its name prefixes indicate the number of each type of atom. so NCl3 is nitrogen trichloride<span>.
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Answer:

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Explanation:

Step 1: Write the reaction for the solution of Mg(OH)₂

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Step 2: Make an ICE chart

We can relate the solubility product constant (Ksp) with the solubility (S) through an ICE chart.

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I                                0                    0

C                              +S                +2S

E                                S                  2S

The solubility product constant is:

Ksp = 5.61 × 10⁻¹² = [Mg²⁺] × [OH⁻]² = S × (2S)² = 4S³

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