Give the products of the reaction of butanal, with: (a) sodium borohydride, in methanol (b) hydrogen cyanide, with catalytic cya
nide (c) potassium dichromate in dilute sulfuric acid; (d) methanol, with a trace of acid catalyst; (e) ethylamine (CH3CH2NH2)
1 answer:
Answer:
Answers are given below
Explanation:
(a) Aldehyde groups are reduced by sodium borohydride in methanol to give alcohol.
So, butanal produces butanol on reaction with sodium borohydride in methanol.
(b) Aldehyde forms cyanohydrin when they are treated with HCN with catalytic cyanide.
(c) Aldehydes are oxidized by potassium dichromate in dil. sulphuric acid to produce carboxylic acid.
(d) Aldehyde produces acetal with methanol and a trace amount of acid catalyst.
(e) Aldehyde gives condensation reaction with to produce imine.
Structures of products for the given reaction has been shown below.
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Answer:
Explanation:
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In this case, according to the Gay-Lussac's gas law, which illustrates the pressure-temperature behavior as a directly proportional relationship:
We can solve for the final pressure as shown below:
Thus, we plug in the initial pressure and temperature and final temperature to obtain:
Which is not among the choices.
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From 15 mol of Silver nitrate, the moles of silver chloride produced have been 15 mol. Thus, option B is correct.
The balanced chemical reaction for the synthesis of silver chloride has been:
From the balanced equation, since there has presence equal moles of silver nitrate and sodium chloride, the moles of silver chloride formed has been equivalent. Thus, 1 mole of silver nitrate gives 1 mole of silver chloride.
The moles of silver nitrate available are,
The moles of silver nitrate produced can be given as:
Thus, the moles of silver chloride produced have been 15 mol. Thus, option B is correct.
For more information about moles produced, refer to the link:
Answer:
Explanation:
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