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bonufazy [111]
2 years ago
11

An average bushel of apples has a mass of 10 kg and contains 5 dozen apples.

Chemistry
1 answer:
Alina [70]2 years ago
3 0

Answer:

Average mass of 6 apple  = 1 kg

Explanation:

Given:

Average mass of 5 dozen apple = 10 kg

Find:

Average mass of 6 apple

Computation:

Average mass of 6 apple  = [Average mass of 1 apple] x [6 apple]

Average mass of 6 apple  = [10/(12 x 5)] x [6]

Average mass of 6 apple  = 1 kg

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Answer:

b12 and d3

Explanation:

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2 years ago
How do test with crash dummies, seat belts, and air bags illustrate newton's first law of motion??
Liono4ka [1.6K]

Answer:

Newton’s law of inertia is illustrated in tests with crash dummies, seat belts, and airbags, wherein the object stays in motion unless there is an unbalanced force applied to it.

Inertia is the main reason why there are seatbelts and airbags in the car. In this case, when the seatbelt is trapped to the passenger, the passenger experiences the same state of motion as the car. If the car accelerates/decelerates, the passenger experiences it too. When the car experiences collision, an unbalance force is acted upon it. This causes the car to stop abruptly, and the passenger shares the same state of motion because of the seatbelt and the airbags that apply the unbalanced force to stop the passenger to go forward.

8 0
2 years ago
(The radioisotope 224Ra decays by alpha emission via two paths to the ground state of its daughter 94% probability of alpha deca
pav-90 [236]

Answer:

a) ²²⁴Ra₈₈ ---> α + ²²⁰Rn₈₆ + Q

b) the Q-value of this reaction is 5.789 MeV

c) the energies (in MeV) of the two associated alpha particles are; 5.69 MeV and 5.449 Mev

       

Explanation:

a)

The decay equation for the alpha decay is expressed as;

²²⁴Ra₈₈ ---> α + ²²⁰Rn₈₆ + Q

b)

Calculate the Q-value (in MeV) of this reaction.

Q = Mparent - Mdaughter -Mg

Q = MRa - MRn -Mg

= 224.020202 - 220.011384 - 4.00260305

= 0.00621495 amu

= 5.789 MeV

therefore the Q-value of this reaction is 5.789 MeV

c)

Energy of alpha particle is expressed as;

E∝ = MQ / ( m + M)

now this is the maximum energy available for the daughter, ²²⁰Rn going to the ground state;

The energy of the alpha particle gives;

E∝  = 220(5.789) / ( 4 + 220) = 5.69 MeV

as given in the question,The other less frequent alpha occurring 5.5% of the time leaves the daughter nucleus in an excited state of 0.241 MeV above the ground state.

Therefore the energy of this alpha is

E∝ = 5.69 - 0.241 = 5.449 Mev

Therefore the energies (in MeV) of the two associated alpha particles are; 5.69 MeV and 5.449 Mev

d)

Sketch of the nuclear decay scheme have been uploaded along side this answer.

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3 years ago
How is percipation related to high and low pressure
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3 0
3 years ago
Read 2 more answers
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