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-BARSIC- [3]
3 years ago
7

After how many places the decimal expansion of 13497/1250 will terminate

Mathematics
2 answers:
jolli1 [7]3 years ago
6 0

Answer:

4 places of decimals.

Step-by-step explanation:

13497.1250 = 10.7976.

Ipatiy [6.2K]3 years ago
5 0

Answer:

4

Step-by-step explanation:

13497/1250

12500 + 997/1250

12500 + 0.7976

12500.7976

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John is driving at a constant speed of 40 miles per hour. How long does it take him to travel 50 miles?
asambeis [7]

Answer:

1 hour and 15 minutes

or

1.25 hr.

Step-by-step explanation:

40 miles ⇒ 1 hr.

50 miles ⇒ total hours

\frac{50}{40} = 1.25 hours

7 0
3 years ago
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Find the slope of the line through each pair of points. <br> (19, −16), (−7, −15)
erik [133]

Point-Slope:

y+16=-1/26*(x-19)

Finding the regular slope:

m=1/-26=0.03846

7 0
3 years ago
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A tank with a capacity of 1000 L is full of a mixture of water and chlorine with a concentration of 0.02 g of chlorine per liter
faltersainse [42]

At the start, the tank contains

(0.02 g/L) * (1000 L) = 20 g

of chlorine. Let <em>c</em> (<em>t</em> ) denote the amount of chlorine (in grams) in the tank at time <em>t </em>.

Pure water is pumped into the tank, so no chlorine is flowing into it, but is flowing out at a rate of

(<em>c</em> (<em>t</em> )/(1000 + (10 - 25)<em>t</em> ) g/L) * (25 L/s) = 5<em>c</em> (<em>t</em> ) /(200 - 3<em>t</em> ) g/s

In case it's unclear why this is the case:

The amount of liquid in the tank at the start is 1000 L. If water is pumped in at a rate of 10 L/s, then after <em>t</em> s there will be (1000 + 10<em>t</em> ) L of liquid in the tank. But we're also removing 25 L from the tank per second, so there is a net "gain" of 10 - 25 = -15 L of liquid each second. So the volume of liquid in the tank at time <em>t</em> is (1000 - 15<em>t </em>) L. Then the concentration of chlorine per unit volume is <em>c</em> (<em>t</em> ) divided by this volume.

So the amount of chlorine in the tank changes according to

\dfrac{\mathrm dc(t)}{\mathrm dt}=-\dfrac{5c(t)}{200-3t}

which is a linear equation. Move the non-derivative term to the left, then multiply both sides by the integrating factor 1/(200 - 5<em>t</em> )^(5/3), then integrate both sides to solve for <em>c</em> (<em>t</em> ):

\dfrac{\mathrm dc(t)}{\mathrm dt}+\dfrac{5c(t)}{200-3t}=0

\dfrac1{(200-3t)^{5/3}}\dfrac{\mathrm dc(t)}{\mathrm dt}+\dfrac{5c(t)}{(200-3t)^{8/3}}=0

\dfrac{\mathrm d}{\mathrm dt}\left[\dfrac{c(t)}{(200-3t)^{5/3}}\right]=0

\dfrac{c(t)}{(200-3t)^{5/3}}=C

c(t)=C(200-3t)^{5/3}

There are 20 g of chlorine at the start, so <em>c</em> (0) = 20. Use this to solve for <em>C</em> :

20=C(200)^{5/3}\implies C=\dfrac1{200\cdot5^{1/3}}

\implies\boxed{c(t)=\dfrac1{200}\sqrt[3]{\dfrac{(200-3t)^5}5}}

7 0
3 years ago
Someone help pretty please!
Nonamiya [84]
The answer is choice B
y > (2/3)x + 1

The boundary line is the equation y = (2/3)x + 1 which can be found through the slope formula to get m = 2/3. Then you use one of the two points on the line to find b = 1. 

The equal sign in y = (2/3)x + 1 changes to a "greater than" sign to indicate two things
A) The shaded region is above the boundary line
B) The boundary line itself is a dashed line to indicate "no solution points on this line"
4 0
3 years ago
Solve the following system of equations.
timofeeve [1]
+8y and -8y cross out.

So the first one is 3x=15
Second one is 2x=10

x=5
Then plug x is one of the equations

2(5)-8y=10
10-8y=10

x=5
y=0
3 0
3 years ago
Read 2 more answers
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