Question

Anyone know the solution to this algebra problem?

Answer 1

Answer:

$x=1$

Step-by-step explanation:

Given: $\frac{512^{x-2} }{(\frac{1}{64})^{3x}} = 512$

To make this easier, we could change the base to a value of 2.

$\frac{2^{9x-18} }{2^{-18x}} = 2^9$

Move the denominator value to the numerator. When you do this, the $-18x$ becomes positive, so you would add it to the value of $9x-18$

$2^{27x-18} = 2^9$

Since the bases are equal to each other, that means the exponential values must be equal to each other.

$27x-18=9$

Solve for $x$.

$27x=27$

$x=1$

Answer 2

Answer:

x=1

Step-by-step explanation: