Anyone know the solution to this algebra problem?
2 answers:
Answer:
Step-by-step explanation:
Given:
To make this easier, we could change the base to a value of 2.
Move the denominator value to the numerator. When you do this, the becomes positive, so you would add it to the value of
Since the bases are equal to each other, that means the exponential values <em>must </em>be equal to each other.
Solve for .
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<u>Answer: </u>
The complete factorization of are 4(x-3y)(x+3y)
<u>Solution:</u>
Given Data:
Take common value in all the three term.so we take 4 as common term in the above expression
Now factorize the expression
Find the two numbers, whose product should be 9 and sum should be -6.
-3,-3 are the numbers which satisfy the above condition.
When we add -3-3=Sum is 6
Product of -3 -3= 9
-3 , -3 satisfies the condition.
So the expression will become as =
Take the common term
x(x-3y)+3y(x-3y)
(x-3y)(x+3y)
hence the complete factorization of are 4(x-3y)(x+3y)