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3 years ago

What is the equation of 21 less than 11 times a number results in seven times a number decreased by 29 what is the number

Mathematics

1 answer:

zlopas [31]3 years ago

4 0

Answer:

x=-2

Step-by-step explanation:

11x-21=7x-29

11x-7x=-29+21

4x=-8

x=-2

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Can someone do this it's hard I need help

sveticcg [70]

10. G (one box below G; one left of D)
11. F (one box below F)
12. F

13. E to F and A to B
14. C to D and E to F
no diagram 2. sorry can't help with the rest :(

6 0

3 years ago

Quiz 2

Maru [420]

2
Lowest to highest (middle number)

3 0

3 years ago

(06.04 MC)

Andru [333]

$\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}$

◉ $\large\bm{ -4}$

$\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}$

Before performing any calculation it's good to recall a few properties of integrals:

$\small\longrightarrow \sf{\int_{a}^b(nf(x) + m)dx = n \int^b _{a}f(x)dx + \int_{a}^bmdx}$

$\small\sf{\longrightarrow If \: a \angle c \angle b \Longrightarrow \int^{b} _a f(x)dx= \int^c _a f(x)dx+ \int^{b} _c f(x)dx }$

So we apply the first property in the first expression given by the question:

$\small \sf{\longrightarrow\int ^3_{-2} [2f(x) +2]dx= 2 \int ^3 _{-2} f(x) dx+ \int f^3 _{2} 2dx=18}$

And we solve the second integral:

$\small\sf{\longrightarrow2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} f(x)dx = 2 \int ^3_{-2} f(x)dx + 2 \cdot(3 - ( - 2)) }$

$\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} 2dx = 2 \int ^3_{-2} f(x)dx + 2 \cdot5 = 2 \int^3_{-2} f(x)dx10 = }$

Then we take the last equation and we subtract 10 from both sides:

$\sf{{\longrightarrow 2 \int ^3_{-2} f(x)dx} + 10 - 10 = 18 - 10}$

$\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx = 8}$

And we divide both sides by 2:

$\small\longrightarrow \sf{\dfrac{2 { \int}^{3} _{2} }{2} = \dfrac{8}{2} }$

$\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx=4}$

Then we apply the second property to this integral:

$\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} f(x)dx = 4}$

Then we use the other equality in the question and we get:

$\small\sf{\longrightarrow 2 \int ^3_{-2} f(x)dx = 2 \int ^3_{-2} f(x)dx = 8 + 2 \int ^3_{-2} f(x)dx = 4}$

$\small\longrightarrow \sf{2 \int ^3_{-2} f(x)dx =4}$

We substract 8 from both sides:

$\small\longrightarrow \sf{2 \int ^3_{-2} f(x)dx -8=4}$

• $\small\longrightarrow \sf{2 \int ^3_{-2} f(x)dx =-4}$

7 0

2 years ago

The circumference of a circle with a radius of 5, using 3.14 for pi, to the nearest tenth

Anuta_ua [19.1K]

Answer:

Your answer is 31.4 units squared

Step-by-step explanation:

By doing 2πr, you'll get your answer.

2*3.14*5 = 2*15.7 = 31.4

3 0

3 years ago

Find the length of diagonal AV in a three-dimensional figure.

katovenus [111]

Answer:

C. 13

Step-by-step explanation:

Apply pythagorean theorem.

Thus:

Diagonal AV = √(12² + 5²)

AV = √(144 + 25)

AV = √169

AV = 13 cm

6 0

2 years ago