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3 years ago

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An office building casts a 90 foot shadow. At the same time of day, a 5 foot woman standing near the building casts an 8 foot sh

adow. What is the approximate height of the building to the nearest foot?

2 answers:

Elenna [48]3 years ago

8 0

Make a ratio:
<span>
Make sure shadow is in same location on both fractions (either numerator or denominator) </span>

x/90=5/8

Cross multiply:

8x=90x5
8x=450
<span>
x=56.25 feet </span>

Therefore, the approximate height of the building to the nearest foot would be 56.25 feet.
<span>
That makes sense, too, because the woman's shadow is taller than she is, but is less than double her height. </span>The building shadow is taller than the building, but it's less than double the height of the building.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.

AURORKA [14]3 years ago

4 0

Answer:56 feet

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

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The sum of the first three terms of geometric sequence is 14. If the first term is 2, find the possible values of the sum of the

Irina18 [472]

Geometric series are in the form of

$a +a*r +a*r^2+...$

Where a is the first term and r is the common ratio .

And it is given that

$2 +2*r +2*r^2=14$

$2r^2+2r-12=0$

$r^2 +r-6=0$

$(r+3)(r-2)=0$

r=-3,2

So the first five terms are

$2+2(-3)+2(-3)^2+2(-3)^3+2(-3)^4 or 2+2(2)+2(2)^2+2(2)^3+2(2)^4$

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2 years ago

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8. What are the advantages of switching a quadratic function from standard form into vertex form?

Airida [17]

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Step-by-step explanation:

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3 years ago

A triangular lot has sides of 215m, 185m, and 125m. Find the measures of the angles at its corners

Vlada [557]

Answer:

The measures of the angles at its corners are $59.1\°,35.4\°,85.5\°$

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of angle A

Applying the law of cosines

$185^{2}= 215^{2}+125^{2}-2(215)(125)cos(A)$

$2(215)(125)cos(A)= 215^{2}+125^{2}-185^{2}$

$cos(A)= [215^{2}+125^{2}-185^{2}]/(2(215)(125))$ $cos(A)=0.513953$

$A=arccos(0.513953)=59.1\°$

step 2

Find the measure of angle B

Applying the law of cosines

$125^{2}= 215^{2}+185^{2}-2(215)(185)cos(B)$

$2(215)(185)cos(B)= 215^{2}+185^{2}-125^{2}$

$cos(B)= [215^{2}+185^{2}-125^{2}]/(2(215)(185))$ $cos(B)=0.81489$

$B=arccos(0.81489)=35.4\°$

step 3

Find the measure of angle C

Applying the law of cosines

$215^{2}= 125^{2}+185^{2}-2(125)(185)cos(C)$

$2(125)(185)cos(C)= 125^{2}+185^{2}-215^{2}$

$cos(C)= [125^{2}+185^{2}-215^{2}]/(2(125)(185))$ $cos(C)=0.0784$

$C=arccos(0.0784)=85.5\°$

3 0

3 years ago