The number of different dinner combinations for each student that are possible is 24
<h3>How many different dinner combinations for each student are possible?</h3>
The given parameters are:
Entree choices = 3
Side dish = 4
Beverage = 2
The number of different dinner combinations for each student that are possible is
Combination = Entree * Side dish * Beverage
This gives
Combination = 3 * 4 * 2
Evaluate
Combination = 24
Hence, the number of different dinner combinations for each student that are possible is 24
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I Dun know I hope u know the answer
Answer:
x = ± 4/5
Step-by-step explanation:
25 x^2 = 16
Divide each side by 25
25 x^2 /25 = 16 /25
x^2 = 16 /25
Take the square root of each side
sqrt(x^2) = ±sqrt(16/25)
We know that sqrt(a/b) = sqrt(a)/ sqrt(b)
x = ±sqrt(16) / sqrt(25)
x = ± 4/5
Answer:
<em>V = 16x² </em>
<em>Width = 12in</em>
<em>Height = 12in</em>
Step-by-step explanation:
Volume of the box is expressed as;
V = Length *Width * height
Given
Length = 16in
Width = x
Height = x
The volume of the box will be expressed as;
V = 16 * x * x
<em>V = 16x² (This gives the required equation)</em>
To get x:
We are given
V = 2304in³
Substitute;
2304 = 16x²
x² = 2304/16
x² = 144
x= √144
x = 12
<em>Hence the width and the height are both 12inches since they are the same.</em>
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For the sma
Answer:
This means that after going around the unit circle once (2π radians), both functions repeat. So the period of both sine and cosine is 2π . Hence, we can find the whole number line wrapped around the unit circle.
Step-by-step explanation:
